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3 years ago

Asking again since I still don’t understand

Mathematics

1 answer:

larisa86 [58]3 years ago

3 0

Answer:

She can only display each item 56 times

Step-by-step explanation:

Since she has 72 stamps and 56 coins to have a even amount of both she can only make 56 displays

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A farm had an area of 35 mi 2 . the farm is 7 miles wide. how long is th farm?

Akimi4 [234]

Answer is 35/7=5
The width is 5 miles long

5 0

3 years ago

V/4 + 7 = 8<br><br> (also if you could maybe give an explanation id appreciate it a lot.)

Rufina [12.5K]

Answer:

Step-by-step explanation:

1. Subtract 7 on both sides

2. multiply by 4 on both sides

3. v = 4

6 0

3 years ago

Read 2 more answers

CAN SOMEONE PLEASE HELP ME SOLVE THESE.<br> ik it’s a lot but i really need some help <br> thank you

Nutka1998 [239]

A 3x+3c
B 9x^2+12x
C -4ab+24a
D 3x-6
E 3x+3
F (x+1)(2x+3)
G x^2+x-6
H 6x^2-31x+18
I 6x-8y+11
J 2x^3+11x^2+17x+6

M=12

40

44

20

250/11

Last one is 33

6 0

3 years ago

Read 2 more answers

How can 5 people share 4 cookies equally?

Volgvan

By giving each person a fraction of a cookie.

4÷5 = 0.80

If ya give 'em 0.80 th of a cookie, it'll be equal!

Thank you ;)

4 0

3 years ago

If a projectile is fired with an initial speed of vo ft/s at an angle α above the horizontal, then its position after t seconds

Elena L [17]

Answer:

a) The bullet hits the ground after 64 seconds.

b) The bullet hits the ground 113,511.7 feet away.

c) The maximum height attained by the bullet is of 16,384 feet.

Step-by-step explanation:

Equations of motion:

The equations of motion for the bullet are:

$x(t) = (v_0\cos{\alpha})t$

$y(t) = (v_0\sin{\alpha})t - 16t^2$

In which $v_0$ is the initial speed and $\alpha$ is the angle.

Initial speed of 2048 ft/s at an angle of 30o to the horizontal.

This means that $v_0 = 2048, \alpha = 30$ .

$x(t) = (v_0\cos{\alpha})t = (2048\cos{30})t = 1773.62t$

$y(t) = (v_0\sin{\alpha})t - 16t^2 = (2048\sin{30})t - 16t^2 = 1024t - 16t^2$

(a) After how many seconds will the bullet hit the ground?

It hits the ground when $y(t) = 0$ . So

$1024t - 16t^2 = 0$

$16t^2 - 1024t = 0$

$16t(t - 64) = 0$

16t = 0 -> t = 0 or t - 64 = 0 -> t = 64

The bullet hits the ground after 64 seconds.

(b) How far from the gun will the bullet hit the ground?

This is the horizontal distance, that is, the x value, x(64).

$x(64) = 1773.62(64) = 113511.7$

The bullet hits the ground 113,511.7 feet away.

(c) What is the maximum height attained by the bullet?

This is the value of y when it's derivative is 0.

We have that:

$y^{\prime}(t) = 1024 - 32t$

$1024 - 32t = 0$

$32t = 1024$

$t = \frac{1024}{32} = 32$

At this instant, the height is:

$y(32) = 1024(32) - 16(32)^2 = 16384$

The maximum height attained by the bullet is of 16,384 feet.

7 0

3 years ago