Answer:
100°C
Explanation:
The following were obtained from the question:
Initial temperature (T1) = 298 K
Initial pressure (P1) = 32.5 Psi
Final pressure (P2) = 40.68 Psi
Final temperature (T2) =..?
The final temperature can be obtained as follow:
P1/T1 = P2/T2
32.5/298 = 40.68/T2
Cross multiply to express in linear form
32.5 x T2 = 298 x 40.68
Divide both side by 32.5
T2 = (298 x 40.68) /32.5
T2 = 373K
Next, we shall convert 373K to celsius.
This is illustrated below:
T(°C) = T(K) – 273
T(K) = 373
T(°C) = 373 – 273
T(°C) = 100°C
Therefore, the temperature of the air inside the tire at 40.68 Psi is 100°C
Answer:Many cases of DMD are caused by mutations in the part of the gene that ... Each son born to a woman with a dystrophin mutation on one of her two X ... of their sons will have a 50 percent chance of developing the disease and so on. ... Usually, girls do not experience the full effects of DMD the way boys do, ... Find your MDA
Explanation:
Answer: His and Lys are deprotonated but Asp will be protonated.
Explanation:
As the pH is given as 7.4 and pK of His is given as 6.00. There will occur a positive charge on His when it's pH < pK therefore, it is neutral at the given pH.
As the pK value of Lys is 10.53 that is greater than the pH of 7.40. Therefore, charge on Lys is positive.
As the pK value of Asp is 3.65 which is less than the pH value of 7.40. Hence, Asp has a negative charge.
Therefore, we can conclude that His and Lys are deprotonated but Asp will be protonated.
1) 2C₆H₆ + 15O₂ = 6H₂O + 12CO₂
2) n(C₆H₆)/2=n(CO₂)/12
n(CO₂)=6n(C₆H₆)
n(CO₂)=6*12.8 mol = 76.8 mol
