Answer:
An electron is a negatively charged subatomic particle and a proton is a positively charged subatomic particle. Positive charge(s) attract negative charge(s) and vice versa. The proton and neutron stay together and attract one another to give the atom an overall charge of zero (neutral). Which is the charge of an atom. When there is an unequal number of protons and neutrons an ion is formed. If the number of protons are more than the electron, a positively charged ion called cation is formed. On the other hand, if the number of electrons are more than the protons a negatively charged ion called anion is formed.
<u>Answer:</u> The chemical equation is written below.
<u>Explanation:</u>
Transmutation is defined as the process in which one chemical isotope gets converted to another chemical isotope. The number of protons or neutrons in the isotope gets changed.
The chemical equation for the reaction of curium-242 nucleus with alpha particle (helium nucleus) follows:
The product formed in the nuclear reaction are californium-245 nucleus and a neutron particle.
First we dissociate the salt
NaOCl ⇒ Na⁺ + OCl⁻
note that [NaOCl] = [OCl⁻]
note that Na⁺ does not undergo hydrolysis so it is a spectator.
OCl⁻ can reform HOCl in an equilibrium, with OCl⁻ acting as the base.
OCl⁻ + H₂O ⇄ OH⁻ + HOCL
<span>Ka for HOCl = 3.0x10^-8, therefore
Kb for OCL</span>⁻ = Kw / (Ka for HOCl)
= 1.0 × 10⁻¹⁴ / 3.0 <span>× 10⁻⁸
= 3.3 × 10⁻⁷
</span>since Kb for OCl⁻ is given, and the pH is given, then [OCl⁻] must be found, and [OCl⁻] = [NaOCl]
convert the pH into [OH⁻]:
pOH = 14 - pH = 14 - 10.3 = 3.7
[OH⁻] = 10^(-3.7) = 1.995 × 10⁻⁴
set up equib table
OCl⁻ + H₂O ⇄ OH⁻ + HOCl
ST x 0 0
+Δ -1.995 × 10⁻⁴ +1.995 × 10⁻⁴ +1.995 × 10⁻⁴
---------------------------------------------------------------------------------
EQ: x -1.995 × 10⁻⁴ 1.995 × 10⁻⁴ 1.995 × 10⁻⁴
Kb = [OH⁻][HOCl] / [OCl⁻]
3.3 × 10⁻⁷ = (1.995 × 10⁻⁴)² / (x -1.995 × 10⁻⁴ )
x = 1.1963 × 10⁻¹ M = [OCl⁻] = [NaOCl]
The concentration of the salt formed, <span>NaOCl,</span> is 1.2 × 10⁻¹ M
Answer:
Mass of Analyte H2C2O4 = 18.18 grams
Explanation:
The balanced equation is:
The Molarity of Oxalic acid needed can be determined using:
Here M1 = Molarity of Oxalic acid
V1 = Volume of oxalic acid
M2 = Molarity of KOH and V2 = Volume of KOH
M1 = ? , V1 = 16.8 mL , M2 = 0.501 M , V2 = 13.54 mL
Put the values and solve for M2,
We are multiplying by 2 because , 1 H2C2O4 needs 2 KOH
Hence Molarity of H2C2O4 =
0.202 M
Molar mass = H2C2O4 = 2x1 +2x12 + 4x16
= 2+24+64 = 90 gram
18.18 gram
