Each mole of C₂H₄ requires 3 moles of O₂ to react.
5.75 moles of C₂H₄ will require:
3 x 5.75 = 17.25 moles
Each mole of gas occupies 22.4 L at STP.
Liters of gas = 17.25 x 22.4
= 3.86 x 10² L
The answer is C.
It doesn't transfer through Thermalizing
The answer is atomic weight !
Answer:
Explanation:
1) Chemical formula of sodium carbonate: <em>Na₂CO₃</em>
2) Ratio of carbon atoms:
- The number of atoms of C in the unit formula Na₂CO₃ is the subscript for the atom, which is 1 (since it is not written).
Hence, the ratio is 1 C atom / 1 Na₂CO₃ unit formula.
This is, there is 1 atom of carbon per each unit formula of sodium carbonate.
3) Calculate the number of moles in 1.773 × 10⁷ carbon atoms
- Divide by Avogadro's number: 6.022 × 10²³ atoms / mol
- number C moles = 1.773 × 10⁷ atoms / (6.022 × 10²³ atoms/mol)
- number C moles = 2.941 × 10⁻¹⁷ mol
Since, the ratio is 1: 1, the number of moles of sodium carbonate is the same number of moles of carbon atoms.
