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kirill [66]
3 years ago
9

Which of the following is true for balancing equations? A. The number of products should be equal to the number of reactants. B.

The properties of products should be the same as the properties of reactants. C. There must be as equal number of compounds on both sides of the equation. D. There must be as equal number of atoms of each element on both sides of the equation.
Chemistry
2 answers:
svetlana [45]3 years ago
8 0

<u>Answer:</u> The correct answer is Option D.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another.

In a chemical reaction, total mass on the reactant side is equal to the total mass on the product side.

It can also be stated that total number of individual atoms on the reactant side must be equal to the total number of individual atoms on product side.

For Example: Formation of water from hydrogen and oxygen gas.

2H_2+O_2\rightarrow 2H_2O

On reactant side:

Number of Hydrogen atoms = 4

Number of Oxygen atoms = 2

On product side:

Number of Hydrogen atoms = 4

Number of Oxygen atoms = 2

Hence, the correct answer is Option D.

AlexFokin [52]3 years ago
5 0

D.) There must be an equal number of atoms of each element on both sides of the equation

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Answer:

84.4g of AgCl

Explanation:

Based on the reaction:

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

<em>2 moles of AgNO₃ and 1 mole of CaCl₂ priduce 2 moles of AgCl and 1 mole of Ca(NO₃)₂</em>

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100g of each reactant are:

AgNO₃: 100g × (1mol / 169.87g) = 0.589 moles

CaCl₂: 100g × (1mol / 110.98g) = 0.901 moles

For a complete reaction of 0.901 moles of CaCl₂ are necessaries 0.901×2 = <em>1.802 moles of AgNO₃. </em>As there are just 0.589moles, <em>AgNO₃ is limitng reactant</em>

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0.589 moles of AgNO₃ produce:

0.589 moles × ( 2 moles AgCl / 2 moles AgNO₃) =

<em>0.589 moles of AgC</em>l. In mass:

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3 years ago
some students believe that teachers are full of hot air. If I inhale 3.5 liters of gas at a temperature of 19 degrees Celsius an
Afina-wow [57]

Answer:

3.97 L

Explanation:

Data obtained from the question include the following:

Initial volume (V1) = 3.5 L

Initial temperature (T1) = 19 °C

Final temperature (T2) = 58 °C

Final volume (V2) =..?

Next, we shall convert celsius temperature to Kelvin temperature. This can be done as shown below:

Temperature (K) = temperature (°C) + 273

T (K) = T (°C) + 273

Initial temperature (T1) = 19 °C

Initial temperature (T1) = 19 °C + 273 = 292 K

Final temperature (T2) = 58 °C

Final temperature (T2) = 58 °C + 273 = 331 K

Finally, we shall determine the new volume of the gas by using Charles' law equation as shown below:

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Initial temperature (T1) = 292 K

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292 x V2 = 3.5 x 331

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V2 = (3.5 x 331) / 292

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Therefore, the new volume of the gas is 3.97 L.

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