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2 years ago

11

find an equation of the line that satisfies the given condition. write the equation in y=mx+b form. passes through points (1,2)

and (3,-4)

1 answer:

Sindrei [870]2 years ago

3 0

Answer:

find the slope of the points,then simply put the answer as m,then choose any (y) from the points and put it as (c)

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Based on a sample of 400 people, 22% owned cats<br><br> The p value is

lana66690 [7]

Answer:

88 people

Step-by-step explanation:

400*22/100

4*22

88 people

3 0

3 years ago

The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth

Liono4ka [1.6K]

Answer:

a) There are 126 different ways are there to select four of the nine computers to be set up.

b) 31.75% probability that exactly three of the selected computers are desktops.

c) 35.71% probability that at least three desktops are selected.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, there are no replacements. Which means that after one of the 9 computers is selected, there will be 8 computers.

Also, the order that the computers are selected is not important. For example, desktop A and desktop B is the same outcome as desktop B and desktop A.

These are the two reasons why the combinations formula is important to solve this problem.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

(a) How many different ways are there to select four of the nine computers to be set up?

Four computers are selected from a set of 9.

So

$T = C_{9,4} = \frac{9!}{4!(9-4)!} = 126$

There are 126 different ways are there to select four of the nine computers to be set up.

(b) What is the probability that exactly three of the selected computers are desktops?

Desired outcomes:

3 desktops, from a set of 5

One laptop, from a set of 4.

So

$D = C_{5,3}*C_{4,1} = 40$

Total outcomes:

From a), 126

Probability:

$P = \frac{40}{126} = 0.3175$

31.75% probability that exactly three of the selected computers are desktops.

(c) What is the probability that at least three desktops are selected?

Three or four

Three:

$P = \frac{40}{126}$

Four:

Desired outcomes:

4 desktops, from a set of 5

Zero laptop, from a set of 4.

$D = C_{5,4}*C_{4,0} = 5$

$P = \frac{5}{126}$

Total(three or four) probability:

$P = \frac{40}{126} + \frac{5}{126} = \frac{45}{126} = 0.3571$

35.71% probability that at least three desktops are selected.

4 0

3 years ago

Triangle ABC has vertices ofA(–6, 7), B(4, –1), and C(–2, –9).Find the length of the median from

Svetradugi [14.3K]

We know that in geometry, a median of a triangle is a line segment joining a vertex to the midpoint<span> of the opposing side. So, in a triangle there are three medians. We will find them.

As shown in the figure below, we have the medians:

P1C
P2A
P3B

We need to find P1, P2 and P3. The </span>midpoint of the segment (x1, y1) to (x2, y2<span>) is:
</span>
$(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})$

Therefore:

For the segment AB:

$P_{1} = ( \frac{4-6}{2}, \frac{7-1}{2})$
$P_{1} = (-1,3)$

For the segment BC:
$P_{2} = ( \frac{4-2}{2}, \frac{-1-9}{2})$
$P_{2} = (1,-5)$

For the segment CA:
$P_{3} = ( \frac{-6-2}{2}, \frac{7-9}{2})$
$P_{3} = (-4,-1)$

We know that the distance d<span> between two points P1(x1,y1) and P2(x2,y2) is given by the formula:
</span>
$d = \sqrt{(x_{2}- x_{1})^{2}+(y_{2}- y_{1})^{2} }$

Then of each median is:

Median P1C:

$d_{1} = \sqrt{(-9-3)^{2}+(-2-(-1))^{2}} = \sqrt{145}$

Median P2A:

$d_{2} = \sqrt{(7-(-5))^{2}+(-6-1)^{2}} = \sqrt{193}$

Median P3B:

$d_{3} = \sqrt{(-1-(-1))^{2}+(4-(-4))^{2} } = 8$

3 0

3 years ago

X+19=13<br><br><br> Find the value of x.

Oliga [24]

To find the value of x we need to use the INVERSE OPERATION of addition which is subtraction. Then we will check our work. lets do it:-

x + 19 = 13
x = ?
13 - 19 = x
<span>13 - 19 = -6</span>
x = - 6

CHECK OUR WORK:-

x + 19 = 13
x = -6
-6 + 19 = 13
We were RIGHT!!

So, x = -6

Hope I helped ya!! xD

4 0

4 years ago

Read 2 more answers

The projectile motion of an object can be modeled using s(t)=gt^2+v0t+s0, where g is the acceleration due to gravity, t is the t

RSB [31]

Answer:

S(t) = -4.9t^2 + Vot + 282.24

Step-by-step explanation:

Since the rocket is launched from the ground, So = 0 and S(t) = 0

Using s(t)=gt^2+v0t+s0 to get time t

Where g acceleration due to gravity = -4.9m/s^2. and

initial velocity = 39.2 m/a

0 = -4.9t2 + 39.2t

4.9t = 39.2

t = 8s

Substitute t in the model equation

S(t) = -49(8^2) + 3.92(8) + So

Let S(t) =0

0 = - 313.6 + 31.36 + So

So = 282.24m

The equation that can be used to model the height of the rocket after t seconds will be:

S(t) = -4.9t^2 + Vot + 282.24

7 0

3 years ago

Read 2 more answers