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2 years ago

11

find an equation of the line that satisfies the given condition. write the equation in y=mx+b form. passes through points (1,2)

and (3,-4)

1 answer:

Sindrei [870]2 years ago

3 0

Answer:

find the slope of the points,then simply put the answer as m,then choose any (y) from the points and put it as (c)

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3 years ago

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nirvana33 [79]

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2 years ago

The graph above is a transformation of the function x2 Write an equation for the function graphed above

lutik1710 [3]

Answer: y=0,5x²-x-1,5.

Step-by-step explanation:

$(-1;0)\ \ \ \ (3;0)\ \ \ \ (1;-2) \ \ \ \ y=ax^2+bx+c\ ?\\\left\{\begin{array}{ccc}a*(-1)^2+b*(-1)+c=0\\a*3^2+b*3+c=0\\a*1^2+b*1+c=-2\end{array}\right \ \ \ \ \ \left\{\begin{array}{ccc}a-b+c=0\ \ (1)\\9a+3b+c=0\ (2)\\a+b+c=-2\ (3)\end{array}\right \\$

We summarize (1) and (3):

$2a+2c=-2\ |:2\\a+c=-1\ \ \ \ \Rightarrow\\a+b+c=-2\\(a+s)+b=-2\\-1+b=-2\\b=-1.$

Substitute b=-1 into (2):

$9a+3*(-1)+c=0\\9a-3+c=0\\9a+c=3\ \ (5).\\$

From (5) subtract (4):

$8a=4\ |:8\\a=0,5.\ \ \ \ \Rightarrow\\$

Substitute a=0,5 into (4):

$0,5+c=-1\\c=-1,5.$

Hense:

y=0,5x²-x-1,5.

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1 year ago