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Solnce55 [7]
3 years ago
14

What does the equation y(hat)= 1+3x predict for a value of x=15

Mathematics
1 answer:
ZanzabumX [31]3 years ago
6 0
Y(15)=1+3*15= 46
just plug the 15 which will give the prediction:)
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Which term describes the figure? Choose 1 answer: Parallel lines Perpendicular lines None of the above​
liubo4ka [24]

Answer:

perpendicular lines

Step-by-step explanation:

because they intersect, they do not go even next to each other forever.

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Graph the line with 3/4 slope<br> passing through the point (2,-2).
S_A_V [24]

Answer:

Step-by-step explanation

x1 = 2, y1 = -2 and m = 3/4

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Multiply each term by 4

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Figure PQRS is a rectangle.
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4th option.

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3 years ago
A restaurant sells burritos for $8.00 each. To buy supplies, the restaurant pays $1.50 for the meat and $1.00 for the other ingr
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isnt it just 2.50$ ?

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3 years ago
Read 2 more answers
Kathy is fencing in her yard that has an area of 800 square feet. Her yard is in the shape of a rectangle where the length is 60
anygoal [31]

Answer:

The dimensions of the yard are W=20ft and L=40ft.

Step-by-step explanation:

Let be:

W: width of the yard.

L:length.

Now, we can write the equation of that relates length and width:

L=5W-60 (Equation #1)

The area of the yard can be expressed as (using equation #1 into #2):

Area=W*L=W*(5W-60) (Equation #2)

Since the Area of the yard is 800 ft^2, then equation #2 turns into:

800=W*(5W-60)

Now, we rearrange this equation:  

800=W*(5W-60)//800=5W^2-60W//5W^2-60W-800=0

We can divide the equation by 5 :

W^2-12W-160=0

We need to find the solution for this quadratic. Let's find the factors of 160 that multiplied yields -160 and added yields -12. Let's choose -20 and 8, since (-20)*8=160 and -20+8=-12. The equation factorised looks like this:

(W-20)(W+8)=0

Therefore the possible solutions are W=20 and W=-8. We discard W=-8 since width must be a positive number. To find the length, we substitute the value of W in equation #1:

5*20-60=40

Therefore, the dimensions of the yard are W=20ft and L=40ft.

7 0
3 years ago
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