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NemiM [27]
2 years ago
11

suppose there are 12 year,14 year,and 16 year cicadas that all appear this yest.after how many years will all three types of cic

ades appear together again?
Mathematics
1 answer:
nasty-shy [4]2 years ago
5 0

We have to find LCM of 12,14,16

Refer to the attachment

LCM=2×2×2×2×3×7=16×21=336years

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3 years ago
Represent the number 1.16 using base ten blocks
Sophie [7]
1 10 block, and 16 little blocks
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BRAINLIESTTTT ASAP!!!!<br><br> Factor 3x²y² − xy² − 2y². Show your work.
taurus [48]
3x²y²-xy²-2y²
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2 years ago
One strange phenomenon that sometimes occurs at U.S. airport security gates is that an otherwise law-abiding passenger is caught
valentinak56 [21]

Answer:

c. 0.16

Step-by-step explanation:

For each passenger there are only two possible outcomes. Either they are caught with a gun, or they are not. The probability of a passenger being caught with a gun is independent from other passengers. So we use the binomial probability distribution to solve this question.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 3000000, p = 0.00001

So

\mu = E(X) = np = 3000000*0.00001 = 30

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{3000000*0.00001*(1-0.00001)} = 5.48

What is the probability that tomorrow more than 35 domestic passengers will accidentally get caught with a gun at the airport?

This probability is 1 subtracted by the pvalue of Z when X = 35. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{35 - 30}{5.48}

Z = 0.91

Z = 0.91 has a pvalue of 0.8186

1 - 0.8186 = 0.1814.

The closest answer is:

c. 0.16

8 0
3 years ago
1. What operation is being used in the equation?<br> x + 15 = 22
Harlamova29_29 [7]
Property of addition I think
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2 years ago
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