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Kamila [148]
3 years ago
7

Help! Please no links or I will report u!!

Mathematics
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

D

Step-by-step explanation:

The range is all of the y values that make a function true. Our graph here starts at y=-2 and then goes up for infinity. This means the range is y ≥ -2. The domain is [0, ∞) because our x values start at 0 and go to infinity. This means the domain is restricted so A is not true, B is not true because the graph does not exist at x = -2.

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S=4lw + 2wh s= 92 l=9 w= 2 solve for H?
lisov135 [29]

Answer: 2

Step-by-step explanation:

96 = 4(5)(4) + 2(4)H

96 = 80 + 8H

96 - 80 = 8H

16 = 8H

16/8 = H

2 = H

Done!

8 0
3 years ago
Can U guys please help with this. :)
V125BC [204]

Answer:

x=0.9

Step-by-step explanation:

1.convert to improper fractions

4x+9/7/3=3x/0.5

2.Apply fraction cross multiply

(4x+9) * 0.5=7/3 * 3x

3. simplify

(4x+9) *0.5 =7x

4.Expand

2x+4.5=7x

5.Subtract 4.5 from both sides

2x=7x-4.5

6.Subtract 7x from both sides

2x-7=7x-4.5-7x

7.Simplify

-5x=-4.5

7.Divide by -5

x=0.9

 

5 0
2 years ago
Compute the line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the l
SIZIF [17.4K]

Answer:

\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}

Step-by-step explanation:

The line integral with respect to arc length of the function f(x, y, z) = xy2 along the parametrized curve that is the line segment from (1, 1, 1) to (2, 2, 2) followed by the line segment from (2, 2, 2) to (−9, 6, 5) equals the sum of the line integral of f along each path separately.

Let  

C_1,C_2  

be the two paths.

Recall that if we parametrize a path C as (r_1(t),r_2(t),r_3(t)) with the parameter t varying on some interval [a,b], then the line integral with respect to arc length of a function f is

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{a}^{b}f(r_1,r_2,r_3)\sqrt{(r'_1)^2+(r'_2)^2+(r'_3)^2}dt

Given any two points P, Q we can parametrize the line segment from P to Q as

r(t) = tQ + (1-t)P with 0≤ t≤ 1

The parametrization of the line segment from (1,1,1) to (2,2,2) is

r(t) = t(2,2,2) + (1-t)(1,1,1) = (1+t, 1+t, 1+t)

r'(t) = (1,1,1)

and  

\displaystyle\int_{C_1}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(1+t,1+t,1+t)\sqrt{3}dt=\\\\=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)(1+t)^2dt=\sqrt{3}\displaystyle\int_{0}^{1}(1+t)^3dt=\displaystyle\frac{15\sqrt{3}}{4}

The parametrization of the line segment from (2,2,2) to  

(-9,6,5) is

r(t) = t(-9,6,5) + (1-t)(2,2,2) = (2-11t, 2+4t, 2+3t)  

r'(t) = (-11,4,3)

and  

\displaystyle\int_{C_2}f(x,y,z)ds=\displaystyle\int_{0}^{1}f(2-11t,2+4t,2+3t)\sqrt{146}dt=\\\\=\sqrt{146}\displaystyle\int_{0}^{1}(2-11t)(2+4t)^2dt=-90\sqrt{146}

Hence

\displaystyle\int_{C}f(x,y,z)ds=\displaystyle\int_{C_1}f(x,y,z)ds+\displaystyle\int_{C_2}f(x,y,z)ds=\\\\=\boxed{\displaystyle\frac{15\sqrt{3}}{4}-90\sqrt{146}}

8 0
3 years ago
Please help me with this equation
natita [175]

Answer:

u just expand the brackets out and make a linear equation to solve from there

Step-by-step explanation:

6 0
3 years ago
Which question is a statistical question?
Gwar [14]

Answer:

C. How many movies do the students in my class watch in a month

Step-by-step explanation:

7 0
3 years ago
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