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sp2606 [1]
3 years ago
11

Matthew has $540 in his bank account. He subscribes to a music streaming service for $7.99 per month. If he makes no other depos

its or withdrawals, what is Matthews new account balance after 5 months of his subscription?
Mathematics
2 answers:
Lady_Fox [76]3 years ago
8 0

Answer:

500.05

Step-by-step explanation:

7.99 x 5 is of course 39.95 and 39.95 - 540 is 500.05 and that's on period

vitfil [10]3 years ago
5 0
7.99 x 5 = 39.95 (40 dollars) 540-39.95 =500.05
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"think through math" 4th grade "answers"
harina [27]
What kind of question is tht ,where is the question
6 0
3 years ago
Read 2 more answers
The mass of a proton is about 1.7 \times 10^(-24). Write this number in standard notation.
OLga [1]

Now we have a negative exponent, which is the opposite of a positive exponent.

If a positive exponent means you're multiplying by 10s and it makes a number bigger by moving the decimal to the right, then

the opposite of this is that a negative exponent means you're dividing by 10s and making the number smaller by moving the decimal point to the left.

 

Examples:

930 \div 10 = 93

{\bf930 \div 10} \div 10 = {\bf 93} \div 10 = 9.3

 

The trick is to recognize that

930 \div 10 is the same thing as 930 \times 10^{-1}

{}\div 10 and {}\times 10^{-1} mean the same thing.

So, 930 {\bf {}\div 10 \div 10} = 930 {\bf {}\times 10^{-1}  \times 10^{-1}} = 930 {\bf {}\times 10^{-2}} = 9.3

 

For your exercise, {}\times10^{-24} means you'll move the decimal point 24 places to the left, to make the number smaller.

3 0
3 years ago
URGENT HELP NEEDED dawg ITS DUE IN 5 MIN can someone help with deal 2? A pizza restaurant offers the following deals. Deal #1 $8
WARRIOR [948]

Answer: Deal one: y = 8.99x + 5 Deal two: y = 6

Step-by-step explanation: I'm not quite sure how you want the equation, but I hope this helps.

6 0
2 years ago
- У
Sedaia [141]
I think it’s probably c d=2 -10
4 0
3 years ago
PLease help!!
weqwewe [10]
√45 + √125

= 3√5 + 5√5

= 8√5

Answer is C.

Hope it helps!
6 0
3 years ago
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