keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

so we're really looking for the equation of a line whose slope is 1/3 and runs through (18,2)

Answer:
hi
Step-by-step explanation:
The answer is B. 13.9. Since M is the midpoint, it splits the line into 2 equal parts.
27.8 / 2 = 13.9
Answer:
In short, Your Answer would be either 1 or 7
Step-by-step explanation:
|4x + 12| = 16
As it is in modulus function, it could be either +ve or -ve
4x+12 = 16 OR 4x - 12 = 16
4x = 16-12 OR 4x = 16 + 12
4x = 4 OR 4x = 28
x = 4/4 OR x = 28/4