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3 years ago

How does an unbalanced force affect an object?please help worth 10 points and will give branlist

Physics

1 answer:

e-lub [12.9K]3 years ago

6 0

Answer:

it can change an objects motion

Explanation:

an unblanaced force can make an object start moving

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When a current is passed through a coil of wire with a piece of iron inside (an electromagnet,a commutator) is formed?

ELEN [110]

When a current is passed through a coil of wire with a piece of iron inside, the one that will be formed is :
an electromagnet
It happens when a soft metal core made into magnet by passage of electric current

hope this helps

6 0

4 years ago

Is the momentum of a car traveling south always the same as the momentum of a car traveling north at the same speed? Explain.

inessss [21]

If the two cars traveling opposite directions have the same mass, then yes, the momentum of a car traveling south will have the same momentum as a car traveling north at the same speed.

8 0

4 years ago

You are riding on a roller coaster that starts from rest at a height of 25.0 m and moves down a frictionless track to a height o

irina [24]

Answer: 20.765 m/s

Explanation:

This problem can be solved by the conservation of energy principle, this means the initial energy $E_{o}$ must be equal to the final energy $E_{f}$ :

$E_{o}=E_{f}$ (1)

Where each energy is the sum of kinetic energy $K$ and potential energy $U$ :

$K_{o}+U_{o}=K_{f}+U_{f}$ (2)

Where:

$K_{o}=\frac{1}{2}mV_{o}^{2}$

Being $m$ your mass and $V_{o}=0 m/s$ your initial velocity, since the roller coaster sterted from rest.

$U_{o}=mgh_{o}$

Being $g=9.8 m/s^{2}$ the acceleration due gravity and $h_{o}=25 m$ your initial height

$K_{f}=\frac{1}{2}mV_{f}^{2}$

Being $V_{f}$ your final velocity

$U_{f}=mgh_{f}$

Being $h_{f}=3 m$ your final height

Rewritting (2):

$\frac{1}{2}mV_{o}^{2}+mgh_{o}=\frac{1}{2}mV_{f}^{2}+mgh_{f}$ (3)

$mgh_{o}=m(\frac{1}{2}V_{f}^{2}+gh_{f})$ (4)

Isolating $V_{f}$ :

$V_{f}=\sqrt{2g(h_{o}-h_{f})}$ (5)

$V_{f}=\sqrt{2(9.8 m/s^{2})(25 m-3 m)}$ (6)

Finally:

$V_{f}=20.765 m/s$ This is your spedd when you arrive at 3 m height

7 0

4 years ago

Gravity always tries to collapse the mass of a star toward its center. What mechanism can oppose this gravitational collapse for

Tamiku [17]

Answer:

The gravity collapsing the core, increases pressure causing the fusion of hydrogen to helium. The newly formed helium creates outward pressure. The pressure balances the gravitational inward pull. This is the hydrostatic equilibrium and it occurs throughout the main sequence phase.

6 0

4 years ago

A race car is one lap behind the lead race car when the lead car has 44 laps to go in a race. If the speed of the lead car is 55

masha68 [24]

Answer:

Speed of second car will be 57.17 m/sec

Explanation:

We have given lead car travels = 44 laps

1 laps = 1.34 km = 1340 m

So total distance = 1340×44 = 58960 m

Speed of lead car = 55.9 m/sec

We know that $time=\frac{distance}{speed}=\frac{58960}{55.9}=1054.74sec$

As the second car is 1 lap behind so distance traveled by second car = 45×1340 = 60300 m

So speed of second car will be $speed=\frac{distance}{time }=\frac{60300}{1054.74}=57.17m/sec$

3 0

3 years ago