Question

A 175-kg motorcycle goes around an unbanked turn of radius 75.4 m at a steady 112 km/h. Determine its acceleration?

Answer 1

Answer: $12.83 m/s^{2}$

Explanation:

In this case we are talking about the centripetal acceleration $a_{c}$, which can be calculated by:

$a_{c}=\frac{V^{2}}{r}$

Where:

$V=112 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}=31.11 m/s$ is the speed of the motorcycle

$r=75.4 m$ is the radius of the path the motorcycle is going around

Solving:

$a_{c}=\frac{(31.11 m.s)^{2}}{75.4 m}$

Finally:

$a_{c}=12.83 m/s^{2}$