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3 years ago

Can positive force of energy be used against negative force of energy. To create continuum of movement.

1 answer:

3 0

There are no rules that can be used to answer that question.
Some of the main reasons include:

-- There's no such thing as the force of energy.
and
-- There's no such thing as negative force.
and
-- The phrase "continuum of movement" is rather vague.

Otherwise, the question is quite intriguing.

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Write a statement about the relationship between

Alex17521 [72]

Answer:Just as wavelength and frequency are related to light, they are also related to energy. The shorter the wavelengths and higher the frequency corresponds with greater energy. So the longer the wavelengths and lower the frequency results in lower energy.

Explanation:So, if the wavelength of a light wave is shorter, that means that the frequency will be higher because one cycle can pass in a shorter amount of time. ... That means that longer wavelengths have a lower frequency. Conclusion: a longer wavelength means a lower frequency, and a shorter wavelength means a higher frequency!

Extra explanation: All waves can be defined in terms of their frequency and intensity. c = λν expresses the relationship between wavelength and frequency.

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3 years ago

A mass of 25kg is moving and is stopped in 1.2 seconds with an acceleration of 1.0 m/s squared what is the force on the mass?

Phantasy [73]

F=ma therefore 25kg*1.0m/s^2=25N force on the mass

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3 years ago

Energy has many different forms: ____________ energy is the energy of motion, for every moving object and living thing; ________

jok3333 [9.3K]

Answer:

1.kinetic

2.potential

3.directly

4.mass

6 0

3 years ago

What do electrons move from

Alona [7]

Answer:

Negatively charged, to positively charged parts

Explanation:

Electrons are negative, negative is attracted to positive.

7 0

3 years ago

A car travelling at 5.0 m/s starts to speed up. After 3.0 s its velocity has increased to 11 m/s. a) What is its acceleration? (

lions [1.4K]

initially, the car is traveling at 5.0 m/s.

so, we know acceleration for changing velocity is :

a = (v-v $_{o}$ )/t ..........(i)

where v is the final velocity

v $_{o}$ is the initial velocity

t is the time taken to change velocity

Now, as per the question :

initial velocity, v $_{o}$ =5.0 m/s

final velocity, v =11 m/s

time taken, t = 3 s

putting the values in equation (i),

a = ( 11-5 )/3

a = 2 m/s²

Therefore, a, after 3 s, is 2 m/s².

4 0

1 year ago