Answer:
The color orange is named after the fruit
Answer:
(A) The period of its rotation is 0.5 s (2) The frequency of its rotation is 2 Hz.
Explanation:
Given that,
a ball is spun around in circular motion such that it completes 50 rotations in 25 s.
(1). Let T be the period of its rotation. It can be calculated as follows :

(2). Let f be the frequency of its rotation. It can be defined as the number of rotations per unit time. So,

Hence, this is the required solution.
Explanation:
Let
is the mass of proton. It is moving in a circular path perpendicular to a magnetic field of magnitude B.
The magnetic force is balanced by the centripetal force acting on the proton as :

r is the radius of path,

Time period is given by :


Frequency of proton is given by :

The wavelength of radiation is given by :


So, the wavelength of radiation produced by a proton is
. Hence, this is the required solution.
<h3><u>Answer;</u></h3>
Higher temperatures
A wave will go faster through a liquid at <em><u>highe</u></em><u>r </u>temperatures
<h3><u>Explanation;</u></h3>
- <em><u>Mechanical waves are types of waves that require a material medium for transmission.</u></em> An example of mechanical wave is the sound wave whose transmission occurs in medium such as solids, liquids and gases.
- <em><u>The transmission of mechanical waves involves vibration of particles through the medium of transmission, thus transfer of energy from one point to another. </u></em>The vibration of particle may be in the form of a longitudinal wave or a transverse wave.
- <em><u>Increasing the temperature in a medium increases the kinetic energy of the particles in the medium and thus increasing the speed at which the particles vibrates and thus aiding a faster transmission of a wave.</u></em>
Answer:
a) α = 0.338 rad / s² b) θ = 21.9 rev
Explanation:
a) To solve this exercise we will use Newton's second law for rotational movement, that is, torque
τ = I α
fr r = I α
Now we write the translational Newton equation in the radial direction
N- F = 0
N = F
The friction force equation is
fr = μ N
fr = μ F
The moment of inertia of a saying is
I = ½ m r²
Let's replace in the torque equation
(μ F) r = (½ m r²) α
α = 2 μ F / (m r)
α = 2 0.2 24 / (86 0.33)
α = 0.338 rad / s²
b) let's use the relationship of rotational kinematics
w² = w₀² - 2 α θ
0 = w₀² - 2 α θ
θ = w₀² / 2 α
Let's reduce the angular velocity
w₀ = 92 rpm (2π rad / 1 rev) (1 min / 60s) = 9.634 rad / s
θ = 9.634 2 / (2 0.338)
θ = 137.3 rad
Let's reduce radians to revolutions
θ = 137.3 rad (1 rev / 2π rad)
θ = 21.9 rev