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Dmitry_Shevchenko [17]
4 years ago
12

Was the color orange named after the fruit or was the fruit named after the color ​

Physics
1 answer:
Marizza181 [45]4 years ago
8 0

Answer:

The color orange is named after the fruit

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A car of mass 940.0 kg accelerates away from an intersection on a horizontal road. When the car speed is 42.5 km/hr (11.8 m/s),
MAVERICK [17]

Answer:

0.39 m/s^2

Explanation:

Parameters given:

Mass of car, m = 940 kg

Speed of car, v = 11.8 m/s

Power supplied by engine, P = 4300 W

To get the acceleration, we must define the relationship between Power and velocity.

Power, P, is given in terms of velocity, v, as:

P = F * v

where F = force

This is because Power is given as:

P = \frac{E}{t} \\\\\\P = \frac{F*d}{t} \\\\\\=> P = F * v

(where E = energy. t = time taken, d = distance moved)

Force, F, is given as:

F = m*a

Therefore, Power will be:

P = m * a * v

Acceleration, a, will then be:

a = \frac{P}{m*v}

a = \frac{4300}{940 * 118} \\\\\\a = 0.39 m/s^2

The acceleration of the car at that time is 0.39 m/s^2

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3 years ago
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Can someone please help me
Delicious77 [7]

Answer:

I am 98% sure that the answers are B and A

Explanation:

6 0
2 years ago
Which planet has a "great red spot"<br>​
bonufazy [111]

the answer is Jupiter

please mark the brainliest

8 0
3 years ago
What statement best describes what it means to maximize your efforts in sports?
Yuliya22 [10]

What statement best describes what it means to maximize your efforts in sports?

D.none of the above

5 0
3 years ago
A projectile travels above level ground. The initial vertical component of its velocity is 0.90 m/s and the initial horizontal c
sladkih [1.3K]
<span>at maximum height the final velocity will be 0 
using v=u+at and resolving vertically we get 
v=0.6+(-9.81)t 
v=0.6-9.81t 
0=0.6-9.81t 
9.81t=0.6 
t=0.6/9.81 
t=0.061 to 3sf 

Now we need to resolve horizontally to find the horizontal distance 
using s=ut+1/2at^2 
However we now need the total time taken for the projectile travel and return to the ground. We can assume the time taken for the projectile to reach its maximum height and return to the ground is the same therefore 
the total time is 2 x 0.061=0.122seconds. They'll be now horizontal acceleration in this case scenario therefore 

Hence s=ut+1/2at^2 
since a=0 
s=ut 
s=0.6 x 0.122 
s=0.073m 
</span>
5 0
3 years ago
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