Answer:
Minutes can provide us the continuous data as we can have the values between the two minutes, in fraction. So if we consider minutes there will be a complete continuous data for the analysis. However the number of cars, trucks, pedestrians, bicyclists, food trucks etc will be in integers as they can not be described in terms of fractions. So for continuous data option (E) is correct.
The number of minutes for a car to get from the intersection to the administration building.
Answer:
7213.7kg/m³
Explanation:
Given parameters:
Volume of the metal chunk = 0.131m³
Mass of the metal chunk = 945kg
Unknown:
Density of the metal chunk = ?
Solution :
To solve this problem, density is the mass per unit volume. It is mathematically expressed as;
Density = 
So;
Density = 
= 7213.7kg/m³
<em>Class I .</em> . .
The fulcrum is between the effort and the load.
The mechanical advantage may be any positive number, more or less than ' 1 '.
<em>Class II .</em> . .
The load is between the fulcrum and the effort.
The mechanical advantage is always greater than ' 1 '.
<em>Class III .</em> . .
The effort is between the fulcrum and the load.
The mechanical advantage is always less than ' 1 '.
Answer:
77.88 lbm/ft³
Explanation:
Given,
Specific gravity, SG = 1.25
Density of water, ρ = 62.30 lbm/ft³
density of the fluid =
= S.G x ρ_{water}
= 62.30 x 1.25
= 77.88 lbm/ft³
Density of the fluid is equal to 77.88 lbm/ft³
