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stich3 [128]
3 years ago
8

What is 0.65 as a fraction or mixed number in simplest form?

Mathematics
2 answers:
alexandr1967 [171]3 years ago
8 0
Please mark me as a brainliest

adell [148]3 years ago
7 0

Answer:

13/20

Step-by-step explanation:

0.65 = 65/100

both are multiples of 5, so simplify:

65/100 = 13/20

-Chetan K

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Reduce the expression by cancelling the common factors: 1/n
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Try this X varies directly as y and jointly as z, and x = 20, when y=3 and z= 4 a. Find the constant b. What is the formula conn
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Answer:

Step-by-step explanation:

as x is direct to y hence

x∝y

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x∝y*z

now insert b as constant

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as given x=20, y=3 , z=4 putt in above equation we get

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How can u show that two objects are proportional using a graph
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The graph has to be a straight line that pass through the origin (0,0)
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3 years ago
❊ Simplify :
DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}

Now, create a common denominator. To do this, we can multiply the first term by (<em>a</em> + 1) and the second term by (<em>a</em> + 2). Hence:

\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}

Add the fractions:

\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}

Factor:

\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}

Simplify:

\displaystyle =\frac{a+4}{(a-1)(a+1)}

We can expand. Therefore:

\displaystyle =\frac{a+4}{a^2-1}

Problem 2)

We want to simplify:

\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}

Again, let's create a common denominator. First, let's factor out a negative from the second term:

\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}

Now to create a common denominator, we can multiply the first term by (<em>a</em> - <em>c</em>) and the second term by (<em>a</em> - <em>b</em>). Hence:

\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}

Subtract the fractions:

\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}

Distribute and simplify:

\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}

Cancel. Hence:

\displaystyle =\frac{1}{(a-b)(a-c)}

4 0
3 years ago
(08.03)jasper is using the following data samples to make a claim about the house values in his neighborhood: house value a $150
ipn [44]

Part A) Jasper should use the median because there is an outlier that affects the mean is the correct answer.

Part B) Option (D) no, because there is a lot of variability in the art book data is the correct answer.

In this question,

Part A)

The median is the middle number in a sorted, ascending or descending list of numbers and can be more descriptive of that data set than the average. The numbers are ordered in ascending order. Once the numbers are ordered, the middle number is called the median of the given data set.

The median is important because it gives us an idea of where the center value is located in a dataset. The median is the most informative measure of central tendency for skewed distributions or distributions with outliers.

The house values in Jasper's neighborhood,

a) $150,000, b) $175,000, c) $200,000 ,d) $167,000, e) $2,500,000

The value of house E is very high from other houses in Jasper's neighborhood. The value of house E will make the mean house value above the center of the data as House E is an outlier for our given data.

Thus the median of a data set with an outlier is not affected by the value of outlier. Therefore, Jasper should use the median because there is an outlier that affects the mean is the correct answer.

Part B)

The mean absolute deviation of a dataset is the average distance between each data point and the mean. It gives us an idea about the variability in a dataset. The mean absolute deviation is specially important in data analysis where the average value can be deceptive.

A small mean absolute deviation tells us that most of the data values are very close to the mean. A high mean absolute deviation tells us that many of the data values are spread out further from the mean.

Magdeline selects 25 pages from each book, then Calculates Mean, Median, Mean Absolute Deviation of number of words on each page.

Book                Mean      Median     Mean Absolute Deviation

Art                      68.7          50                   15.4

Science             54.2          55                    7.9

Magdeline claims that the mean number of words on each page in the art book is greater than the mean number of words on each page in the science book, the art book has more words per page is not a valid inference.

Because variability from mean in art book is more than variability from mean in science book and the mean absolute deviation measures variability from mean. Thus option (D) no, because there is a lot of variability in the art book data is the correct answer.

Learn more about mean absolute deviation here

brainly.com/question/1468924

#SPJ4

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2 years ago
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