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bearhunter [10]
3 years ago
12

The metric system is based on multiples of 100. Please select the best answer from the choices provided A.True B.False

Mathematics
1 answer:
Otrada [13]3 years ago
5 0

Answer:

true

Step-by-step explanation:

i think

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Which measurement is equivalent to 6500 grams A 0.65 kg B 6.5 kg C 65 kg D 650 kg
Crazy boy [7]
B) because 1000g= 1kg
so 6500g=6.5kg
4 0
3 years ago
Pleaseee help with this
KiRa [710]

Answer:

g(x) = (x + 1)^2 + 3

Step-by-step explanation:

When x is replaced by x - h, it results in a horizontal translation of h units.

When y is replaced by y - k, it results in a vertical translation of k units.

f(x) = x^2 is the original function.

Rewrite it as

y = x^2

To translate it 1 unit left, you need h = -1.

x - h = x - (-1) = x + 1. Replace x with x + 1.

Now you have y = (x + 1)^2.

To translate 3 units up, you have k = 3.

y - k = y - 3. Replace y with y - 3.

y - 3 = (x + 1)^2

Solve for y.

y = (x + 1)^2 + 3

Replace y with g(x).

g(x) = (x + 1)^2 + 3

8 0
3 years ago
Harry Potter has a large amount of money in his vault at Gringotts. He wants to use some of it to buy his friends new broomstick
lianna [129]

Answer:

Domain is 8 to 15 broomsticks

Range is 1,200 to 2,250 Galleons

Step-by-step explanation:

Here, when we talk of the domain, we are simply referring to the range of values of the number of broomsticks to be bought which is between 8 and 15

When we talk of the range, we are talking of the amount these broomsticks will cost

The cost for 8 broomsticks will be 8 * 150 = 1,200 Galleons

15 broomsticks will cost 15 * 150 = 2,250 Galleons

The range here will thus be 1,200 Galleons to 2,250 Galleons

7 0
3 years ago
Read 2 more answers
Kylie bought 10 chicken wings for $15. What was the cost of the wings in wings per dollar?
Reil [10]

Answer: $2.50

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The Office of Student Services at a large western state university maintains information on the study habits of its full-time st
Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 20 hours, standard deviation of 6:

This means that \mu = 20, \sigma = 6

Sample of 150:

This means that n = 150, s = \frac{6}{\sqrt{150}}

What is the probability that the mean of this sample is between 19.25 hours and 21.0 hours?

This is the p-value of Z when X = 21 subtracted by the p-value of Z when X = 19.5. So

X = 21

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{21 - 20}{\frac{6}{\sqrt{150}}}

Z = 2.04

Z = 2.04 has a p-value of 0.9793

X = 19.5

Z = \frac{X - \mu}{s}

Z = \frac{19.5 - 20}{\frac{6}{\sqrt{150}}}

Z = -1.02

Z = -1.02 has a p-value of 0.1539

0.9793 - 0.1539 = 0.8254

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

3 0
3 years ago
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