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Alex_Xolod [135]

2 years ago

10

The speed (v) of a gear varies inversely as the number of teeth (t). If a gear that has 48 teeth makes 20 revolutions per minute

, how many revolutions per minute will a gear that has 30 teeth make?
I give Brainliest! Please show work too.

1 answer:

Svetradugi [14.3K]2 years ago

3 0

Answer:

80

Step-by-step explanation:

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What do 89/90 equal but not as a decimal or a percent as a fraction HELP ME

sergeinik [125]

Answer:

it equals 89/90

Step-by-step explanation:

the gcf of 89, 90 is 1, so the fraction can not be simplified. The answer is 89/90.

3 0

2 years ago

What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =

son4ous [18]

one angle is 3x-3

another angle is 6(x-10)

Both angles are vertically opposite angles

Vertically opposite angles are always equal

So we equation both the angles and solve for x

3x - 3= 6(x-10)

3x - 3 = 6x - 60

Subtract 6x from both sides

-3x - 3 = -60

Add 3 on both sides

-3x = -57

Divide by 3

x = 19

The value of x= 19

3 0

3 years ago

What is the solution to the system <br><br> A. (-3,1)<br> B. (0,3<br> C. (1,3)<br> D. (1,-1)

UNO [17]

Answer:

C

Step-by-step explanation:

the lines are intersecting at 1,3

5 0

2 years ago

Read 2 more answers

18x^2+24x=0 Please solve by factoring.

Harman [31]

Answer:

6x ( 3x +4)

X =0 and x = 4/3 or x = 1 1/3

Step-by-step explanation:

Take the common factors out,

Here x is common to both equation and also 6 is common to both equation

So,

6x ( 3x + 4) = 0

So it can be solved by

X = 0 and x = 4/3

4 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

2 years ago