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Furkat [3]
3 years ago
14

A student needs to make 0.855 L of a sodium bromide solution for an experiment. The concentration of the required solution is 0.

350 M. How many grams of sodium bromide will he need to use?
Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
4 0

Answer:

Explanation:

Molarity =  moles/liters of solution

moles    = molarity x Liters of solution

            =  0.350 m/L x 0.855 L

            =  0.299 mol

               mass = moles  x  molar mass    

            = 0.299 mol x 102.89 g/ms

            =  30.78 grams

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Answer: The decay energy is the energy released by a radioactive decay. Radioactive decay is the process in which an unstable atomic nucleus loses energy by emitting ionizing particles and radiation.

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Two identical syringes are filled to the same volume at the same temperature and pressure. If one
Semmy [17]

The temperature is the same, so the amount of kinetic energy will also be the same.

7 0
2 years ago
2HCl + CaCO3 → CaCl2 + H2O + CO2
zloy xaker [14]

Answer:

The amount of CaCl2 produced depends on the amount of HCl in the reaction.

Explanation:

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4 0
3 years ago
How many mL of 3.0M HCl are needed to make 300.0 mL of a 0.10M HCl?
nalin [4]

Answer:

V₁  = 10 mL

Explanation:

Given data:

Initial volume of HCl = ?

Initial molarity = 3.0 M

Final molarity = 0.10 M

Final volume = 300.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of HCl

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

3.0 M ×V₁  =  0.10 M×300.0 mL

3.0 M ×V₁  = 30 M.mL

V₁  = 30 M.mL /3.0 M

V₁  = 10 mL

3 0
3 years ago
1.00 mole of oxygen at 60 degrees celcius and 5 bar is flowing through a 20cm diameter pipe (inner diameter). What is the veloci
jeka94

Answer:

u = 0.176 m/x

Explanation:

∴ n O2 = 1 mol

∴ mass O2 = 1 mol * 32 g/mol = 32 g

∴ T = 60°C = 333 K

∴ P = 5 bar

⇒ V = RTn/P = (83.14 bar.cm³/mol.K)*(333 K)*(1 mol))/(5 bar)

⇒ V = 5537.124 cm³

∴ d = 20cm

⇒ A = (1/4π)*d² = 314.16 cm²

velocity of the gas (m/x):

  • u = m / ρ*A
  • let time (t) = x sec

∴ ρ = 32 g / 5537.124 cm³ = 5.78 E-3 g/cm³

∴ mass flow rate (m) = 32g / x

⇒ u = (32 g/x) / (( 5.78 E-3 g/cm³)*(314.16cm²))

⇒ u = 17.625 cm/x * ( m/100cm) = 0.176 m/x

4 0
3 years ago
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