A student needs to make 0.855 L of a sodium bromide solution for an experiment. The concentration of the required solution is 0.
350 M. How many grams of sodium bromide will he need to use?
1 answer:
Answer:
Explanation:
Molarity = moles/liters of solution
moles = molarity x Liters of solution
= 0.350 m/L x 0.855 L
= 0.299 mol
mass = moles x molar mass
= 0.299 mol x 102.89 g/ms
= 30.78 grams
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