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3 years ago

What is the strongest intermolecular force present in SO2? (EN Values: S = 2.5; O = 3.5). Please explain!

Chemistry

1 answer:

Afina-wow [57]3 years ago

5 0

Answer:

Dipole-Dipole force

Explanation:

Dipole - Dipole force -

These are the force of attraction , that occurs between two dipole , i.e. ,a species with two poles , hence , the attraction between the delta positive charge of first species with the delta negative charge of the second species , arises to a dipole - dipole force of attraction.

Hence, from the question,

SO₂ , is a polar compound , where O is more electronegative in comparison to S , thus , O attains a delta negative charge and S attains a delta positive charge and therefore , generates a dipole , and interacts with the dipole of the second molecule of SO₂ , arising a dipole - dipole force of attraction .

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which part of the mushroom gathers nutrients from the soil or dead material that the mushroom is decomposing?

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Answer:

The Mycelium is usually hidden in the soil, in wood, or another food source. A Mycelium may fill a single ant or cover many acres.

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3 years ago

How many moles of sodium carbonate in 18.06x10 to the power 22

igor_vitrenko [27]

Answer:

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3 years ago

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What is the best definition of biology?

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Answer:

Explanation:

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3 years ago

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At 24°C, Kp = 0.080 for the equilibrium: NH4HS (s) NH3 (g) + H2S (g) A sample of solid NH4HS is placed in a closed vessel and al

miss Akunina [59]

Answer:

Partial pressure of ammonia is 0,28.

Explanation:

For the reaction:

NH₄HS(s) ⇄ NH₃(g) + H₂S(g)

kp = 0,080 is defined as:

0,080 = P[NH₃] P[H₂S] <em>(1)</em>

Where P[NH₃] is partial pressure of NH₃

Asuming amount of NH₄HS is 1, equilibrium concentration for each compound is:

[NH₄HS] = 1 - x

P [NH₃] = x

P [H₂S] = x

Replacing in (1):

0,080 = X×X

0,080 = X²

X = 0,28 = P[NH₃]

I hope it helps

7 0

3 years ago

If 12.85 g of chromium metal is reacted with 10.72 g of phosphoric acid, then what is the maximum mass in grams of chromium(III)

RUDIKE [14]

<h3>Answer:</h3>

16.02 g

<h3>Explanation:</h3>

<u>We are given;</u>

Mass of chromium as 12.85 g
Mass of phosphoric acid as 10.72 g

We are require to calculate the maximum mass of chromium (III) phosphate that can be produced.

The equation for the reaction is;

2Cr(s) + 2H₃PO₄(aq) → 2CrPO₄(s) + 3H₂(g)

<h3>Step 1: Determining the number of moles of Chromium and phosphoric acid</h3>

Moles = Mass ÷ Molar mass

Molar mass of chromium = 52.0 g/mol

Moles of Chromium = 12.85 g ÷ 52.0 g/mol

= 0.247 moles

Molar mass of phosphoric acid = 97.994 g/mol

Moles of phosphoric acid = 10.72 g ÷ 97.994 g/mol

= 0.109 moles

<h3>Step 2: Determine the rate limiting reactant </h3>

From the equation, 2 moles of chromium reacts with 2 moles of phosphoric acid.
Therefore, 0.247 moles of Chromium will require 0.247 moles of phosphoric acid, but we only have 0.109 moles.

This means chromium is in excess and phosphoric acid is the rate limiting reagent.

<h3>Step 3: Moles of Chromium(III) phosphate</h3>

From the equation, 2 moles of phosphoric acid reacts to yield 2 moles of chromium (III) phosphate.
Therefore, Moles of Chromium (III) phosphate = Moles of phosphoric acid

Hence; moles of CrPO₄ = 0.109 moles

<h3>Step 4: Maximum mass of CrPO₄ that can be produced</h3>

We know that, mass = Moles × Molar mass

Molar mass of CrPO₄ = 146.97 g/mol

Thus,

Mass of CrPO₄ = 0.109 moles × 146.97 g/mol

= 16.02 g

Thus, the maximum mass of CrPO₄ that can be produced is 16.02 g

7 0

4 years ago