Solve x:(x+4)/3=2 Will give points

2 answers:

8 0

$\frac{x + 4}{3} = 2 \\ \\ \\ \text{ Multiply by 3 on both sides, }\\ \\ \\ = > \frac{x + 4}{3} \times 3 = 2 \times 3 \\ \\ \\ \\ = > x + 4 = 6 \\ \\ \\ = > x = 6 - 4 \\ \\ \\ = > x = 2$

Hence, value of x in the given equation is 2

Oksana_A [137]2 years ago

6 0

(X+4)/3=2
-4. -4
X/3=(-2)
x3. x3
X=6

Step one: isolate x
- take away 4. What you do to one side, you must do to the other. This leaves you with [x/3=(-2)] because 2-4=(-2)
- multiply by 3. This gets rid of the three so x is by itself. Once again, what you do to one side of the equal sign, you must do to the other. It leaves you with [x=6] because 3x(-2)=6

You might be interested in

Use the probability distribution table to answer the question.

ludmilkaskok [199]

Answer:

1. 0.21 like that has happened

6 0

2 years ago

If AB=BA= I then write the relation between matrix A and matrix B

butalik [34]

Answer:

If AB = BA = I, then B is inverse of A and vice-versa.

Step-by-step explanation:

Given: AB = BA = I

To find: The relation between matrix A and B.

If AB = BA = I, then B is called the inverse matrix of A and is denoted by $A^{-1}$ .

In that case, A is said to be invertible.

Also, if B is the inverse of A, then A is also the inverse of B.

Hence, the relation between A and B is that both are inverse of each other.

6 0

2 years ago

Julie bought 3.5 pounds of cheese for $7.49. how much was the cheese per pound

snow_lady [41]

$2.14 per pound is the answer I found. Hope that helps.

6 0

2 years ago

Read 2 more answers

|x|, if x=10; .3; 0; −2.7; −9

alekssr [168]

Answer:

For $\left | x \right |$ we will have positive values only.

$\left | -2.7 |\right =2.7$

$\left | -9 |\right =9$

Rest are positive so will give positive values out of the modulus function.

Step-by-step explanation:

The absolute value of any number is its positive value only.

As for example $(-2.7)$ and $(2.7)$ both are having equal distance from $0$ in a number line, one on the left other on the right side of the number line but are equidistant from $0$ .