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3 years ago

13

Cho một lượng hỗn hợp CuO và Fe2O3 tác dụng hết với dung dịch HCl thu được 2 muối có tỉ lệ mol là 1 : 1. Phần trăm khối lượng củ

a CuO và Fe2O3 trong hỗn hợp lần lượt là:

1 answer:

oksian1 [2.3K]3 years ago

4 0

Answer:

fafsafwafsxDlmfao

Explanation:

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3 years ago

Which of the following is an example of convection?

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Hot air rising and cooler air falling.

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How many liters of oxygen gas can react with 84.0 grams of lithium metal at standard temperature and pressure? Show all of the w

ddd [48]

From the equation:
4mol Li react with 1 mol O2
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mol in 84g Li = 84/7 = 12 mol Li
From the equation - 12 mol Li will react with 3 mol O2

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3 years ago

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Explain some of the benefits and problem associated with the pesticide DDT.

Dafna1 [17]

Some benefits are that DDT helps us grow crops and keeps pests off our crops.

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3 years ago

If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?

myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30.17}\ year^{-1}$

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Initial concentration $[A_0]$ = ?

Final concentration $[A_t]$ = 12.5 grams

Applying in the above equation, we get that:-

$12.5\ g=[A_0]e^{-0.02297\times 90.6}$

$[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g$

<u>Mass of original sample = 100 g</u>

8 0

3 years ago