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ANEK [815]
2 years ago
13

Cho một lượng hỗn hợp CuO và Fe2O3 tác dụng hết với dung dịch HCl thu được 2 muối có tỉ lệ mol là 1 : 1. Phần trăm khối lượng củ

a CuO và Fe2O3 trong hỗn hợp lần lượt là:
Chemistry
1 answer:
oksian1 [2.3K]2 years ago
4 0

Answer:

fafsafwafsxDlmfao

Explanation:

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Suppose you need to prepare 136.9 mL of a 0.315 M aqueous solution of NaCl.
Varvara68 [4.7K]

Answer:

2.52 g NaCl

Explanation:

(Step 1)

To find the mass, you first need to find the moles NaCl. This value can be found using the molarity ratio:

Molarity = moles / volume (L)

After you convert mL to L, you can plug the given values into the equation and simplify to find moles.

136.9 mL / 1,000 = 0.1369 L

Molarity = moles / volume

0.315 M = moles / 0.1369 L

0.0431 = moles

(Step 2)

Now, you can use the molar mass to convert moles to grams.

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

0.0431 moles NaCl           58.443 g
------------------------------  x  -------------------  =  2.52 g NaCl
                                            1 mole

4 0
2 years ago
How many TOTAL atoms are in the following molecule? NaHCO3
blagie [28]

Answer:

NaHCO3 = No. of atoms are 1 sodium + 1 Hydrogen + 1 carbon + 3 oxygens = 6 atoms per molecule.

6 0
3 years ago
The partial negative charge at one end of a water molecule is attracted to the partial positive
Neporo4naja [7]

Answer:

             Hydrogen Bond

Explanation:

                   Hydrogen bond interactions are formed between the hydrogen atom bonded to most electronegative atoms (i.e. F, O and N) of one molecule and most electronegative atom (i.e. F, O and N) of another molecule.

In this interaction the hydrogen atom has partial positive charge and electronegative atom has partial negative charge.

6 0
2 years ago
What do radio waves and microwaves have in common?
Anastasy [175]
1) A
2)A
3)C
4)A
That should be all of them. Hope this helps?
6 0
3 years ago
Information related to a titration experiment is given in the balanced equation and table below.
Scorpion4ik [409]

Answer:

0.24M

Explanation:

The equation for the reaction is given below:

H2SO4 + 2KOH → K2SO4 + 2H2O

From the equation above, we obtained the following information:

nA (mole of acid) = 1

nB (mole of base) = 2

Data obtained from the question include:

Va (volume of the acid) = 12mL

Ca (concentration of the acid) =?

Vb (volume of the base) = 36mL

Cb (concentration of the base) = 0.16 M

The Ca (concentration of the acid) can be obtained as follow:

CaVa/CbVb = nA/nB

Ca x 12 / 0.16 x 36 = 1 /2

Cross multiply to express in linear form as shown below:

Ca x 12 x 2 = 0.16 x 36

Divide both side by 12 x 2

Ca = 0.16 x 36/ 12 x 2

Ca = 0.24M

Therefore, the concentration of the acid is 0.24M

6 0
3 years ago
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