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shusha [124]
3 years ago
13

What are atoms made of

Chemistry
1 answer:
navik [9.2K]3 years ago
3 0
Protons, nuetrons, and electrons

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5.For each of the following, give the name of an element from Period 4 (potassium to krypton), which matches the description.
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an element with a fixed valency of 2 that not is not in group 2

Help
4 0
3 years ago
NEED HELP ASAP
Fantom [35]

Answer:

D. potential

Explanation:

D. potential

5 0
2 years ago
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Give chemical equation representing ionisation of carbonic acid
boyakko [2]

Answer:

HCO3− + OH− ⇌ CO32− + H2O

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6 0
3 years ago
The heat of vaporization of water is 40.66 kJ/mol. How much heat is absorbed when 3.11 g of water boils at atmospheric pressure?
Roman55 [17]

Answer:

The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.

Explanation:

A molar heat of vaporization of 40.66 kJ / mol means that 40.66 kJ of heat needs to be supplied to boil 1 mol of water at its normal boiling point.

To know the amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure, the number of moles represented by 3.11 g of water is necessary. Being:

  • H: 1 g/mole
  • O: 16 g/mole

the molar mass of water is:

H₂O= 2* 1 g/mole + 16 g/mole= 18 g/mole

So: if 18 grams of water are contained in 1 mole, 3.11 grams of water in how many moles are present?

moles of water=\frac{3.11 grams*1 mole}{18 gramos}

moles of water= 0.1728

Finally, the following rule of three can be applied: if to boil 1 mole of water at its boiling point it is necessary to supply 40.66 kJ of heat, to boil 0.1728 moles of water, how much heat is necessary to supply?

heat=\frac{0.1728 moles*40.66 kJ}{1 mole}

heat= 7.026 kJ

<u><em>The amount of heat that is absorbed when 3.11 g of water boils at atmospheric pressure is 7.026 kJ.</em></u>

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