Calculate the net change in enthalpy for the formation of one mole of acrylic acid from calcium carbide, water and carbon dioxid
e from these reactions.
1 answer:
<span>Answer:
2COâ‚‚ (g) + 6Hâ‚‚ (g) → CHâ‚OCHâ‚ (g) + 3Hâ‚‚O (â„“)
Now make this reaction up from what you are given:
2 Ă— (COâ‚‚ (g) + 3Hâ‚‚ (g) → CHâ‚OH (l) + Hâ‚‚O (â„“).. â†H° = –131 kJ)
... (2CHâ‚OH (l) → CHâ‚OCHâ‚ (g) + Hâ‚‚O (â„“) .. â†H° = 8kJ)
––––––––––––––––––––––––––––––––––––––... add
2COâ‚‚ (g) + 6Hâ‚‚ (g) → CHâ‚OCHâ‚ (g) + 3Hâ‚‚O (â„“) . - exactly what you want!
â†H° = 2(–131 kJ) + 8 kJ = –254 kJ</span>
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The answer would be D carbon dioxide
First convert the kg to g ----- 0.03kg = 30g
Then divide the mass by the volume ----- 30g ÷ 25mL = 1.2
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