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otez555 [7]
3 years ago
10

A double-replacement reaction takes place when aqueous K2SO4 reacts with aqueous Pb(NO3)2. You would expect one of the products

of this reaction to be:
Question 3 options:

CNO3.

PbSO4.

K2S.

NaPb.
Chemistry
2 answers:
STALIN [3.7K]3 years ago
6 0

The answer is:  ( PbSO4 ) Hope this helps(:

melomori [17]3 years ago
5 0

A double displacement reaction is one in which the positive and negative ion in one reactant switch places with the positive and negative ions of the second reactant forming two new products.

In general if we have two reactants AB and CD, the double displacement reaction can form the following products:

A⁺B⁻ + C⁺D⁻ → C⁺B⁻ + A⁺D⁻

In the given example:

K₂SO₄ + Pb(NO₃)₂ → PbSO₄ + 2KNO₃

Ans: B)

One of the products would be PbSO₄

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3 0
3 years ago
In a mixture of He, Ne, and Kr the total pressure is 125 kPa. The partial
tatiyna

Answer:

Partial pressure of He = 73 kPa

Explanation:

Given:

Total pressure = 125 kPa

Partial  pressure of Ne = 31 kPa

Partial pressure of Kr = 21 kPa

Find:

Partial pressure of He

Computation:

Total pressure = Partial  pressure of Ne + Partial  pressure of Kr + Partial  pressure of He

125 kPa = 31 kPa + 21 kPa + Partial pressure of He

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