You would plug them in and see if they work. B and D work
Answer: After 1 year: $5,610
After 2 years: $5,722.20
Step-by-step explanation: Use the formula for periodic compounding interest, which is
A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.
Here, P = 5,500, r = 0.02 (that's 2% as a decimal), n = 1,
t = 1 for the first answer, t = 2 for the second answer (1 year, then for 2 years)
Plug the known values in to solve...
For 1 year...
A = 5,500(1 + 0.02/1)^(1*1)
A = 5,500(1.02)^1
A = 5,610
For 2 years...
A = 5,500(1 + 0.02/1)^(1*2)
A = 5,500(1.02)²
A = 5,722.20
Answer:
Step-by-step explanation:
if i had to guess i would say a
Roarrrrtrrtrrrtrt roarrrrtrtt
Answer:
2.4 hours
Step-by-step explanation:
Let total work = X
Rate of work done = X ÷ time
Rate of A = X/4
Rate of B = X/6
If they work together, rate is the sum of their individual rates, i.e.
X/4 + X/6
= (3X + 2X)/12 (taking LCM)
=5X/12
Rate = X/time
5X/12 = X/time
time = X÷(5X/12)
time = X × 12/(5X)
time = 2.4 hours
Shortcut:
Product of individual times/sum of individual times
= (4×6)/(4+6)
=24/10
=2.4 hours
