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ruslelena [56]
3 years ago
10

2x − 1 < 7 and 3x + 24 ≥ 12

Mathematics
1 answer:
balu736 [363]3 years ago
7 0

Answer:

The correct answer by solving with the System of Inequalities is -4\leq x

Step-by-step explanation:

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A rectangle is inscribed in a semicircle of radius 10 as shown in the figure. Find a function that models the area A of the rect
monitta
So based on your question where there is a rectangle inscribed in a semicircle or a radius 10 as shown in your figure. The possible function that could represent the are of the rectangle is A=2x*sqrt(100-x^2) i hope you are satisfied with my answer and feel free to ask for more
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A binomial experiment has 5 trials in which p = 0.7. What is the
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Answer:

Answer

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InesWalston

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Answer with Step-by-step explanation:

For a given Binomial event with  probability of success 'p' the probabolity of 'r' success in 'n' trails is given by

Thus for given 4 trails (n = 4) we have

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Part 2)

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Step-by-step explanation:

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3 years ago
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ArbitrLikvidat [17]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
Let f(x)= 100 / −10+ e^ −0.1x . What is f(−6) ?
bija089 [108]

The value of f(-6) is -12.2

Explanation:

Given that the function f(x)=\frac{100}{-10+e^{-0.1\left(x\right)}}

We need to determine the value of f(-6)

The value of f(-6) can be determined by substituting the value for x=-6 in the function and simplify the function.

Hence, let us substitute x=-6 in the function, we get,

f(-6)=\frac{100}{-10+e^{-0.1\left(-6\right)}}

Let us apply the rule -\left(-a\right)=a , we get,

f(-6)=\frac{100}{-10+e^{0.1\left(6\right)}}

Multiplying the numbers, we get,

f(-6)=\frac{100}{-10+e^{0.6}}

The value of e^{0.6}=1.822

Substituting the value of e^{0.6}=1.822 , we get,

f(-6)=\frac{100}{-10+1.822}

Subtracting the denominator, we have,

f(-6)=\frac{100}{-8.178}

Dividing, we have,

f(-6)=-12.228

Rounding off to the nearest tenth, we have,

f(-6)=-12.2

Thus, the value of f(-6) is -12.2

4 0
3 years ago
Which sequence of transformations will produce similar but not congruent figures?
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