So for example B(4,1) so x=4, y=1
->B'(4-2,1-4)
->B'(2,-3)
->A'(1-2,1-4)
->A'(-1,-3)
->C'(4-1,-2-4)
->C'(3,-6)
->D'(1-2,-2-4)
->D'(-1,-6)
so the image of the rectangle ABCD->A'B'C'D'
Answer:
Step-by-step explanation:
b = 5655
r = 1.4% = 1.4/100 = 0.014
Therefore, the equation would be
y = 5655(1 + 0.014)^t
y = 5655(1.014)^t
b) in 2022, t = 2022 - 2010 = 12 years
y = 5655(1.014)^12
y = 6682
Answer:
X =51 is the best answer for this question
If Sin 60 = √3 / 2
Then, Cos 60 = ?
Well, we know :
Sin^2x + Cos^2x = 1
Let X = 60°
That is,
Sin^2(60) + Cos^2(60) = 1
(√3 / 2)^2 + Cos^2(60) = 1
3 / 4 + Cos^2(60) = 1
Cos^2(60) = 1 - 3/4
Cos^2(60) = 4/4 - 3/4
Cos^2(60) = (4-3)/4
Cos^2(60) = 1/4
Cos(60) = √(1/4)
Cos(60) = √1 / √4
Cos(60) = 1 / 2
This's answer right to the your question.
Answer:
D. 64
Step-by-step explanation:
I calculated it logically