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Savatey [412]
3 years ago
5

Find the area of this figure to the nearest hundredth. Use 3.14 to approximate pi.

Mathematics
1 answer:
Fantom [35]3 years ago
4 0

Answer:

49.12 square units

Step-by-step explanation:

Area of triangle = \dfrac{1}{2}*base *height

                          =\dfrac{1}{2}*6*8=3*8 = 24 \ sq.units

Circle:

d = 8 units

r = 8/2 = 4 units

Area \ of \  semicircle = \dfrac{1}{2}\pi r^{2}\\

                                =\dfrac{1}{2}*3.14*4*4=3.14*2*4= 25.12 \ sq.units

Area of the figure = area of triangle +area of semicircle

   = 24 + 25.12

    = 49.12 sq. units

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Find the greatest common factor of 10, 30 and 45
lawyer [7]

Answer:

The greatest common factor is 5.

Step-by-step explanation:

The prime factorisation of 10, 30 and 45 is,

10 = 2 × 5

30 = 2 × 3 × 5

45 = 3 × 3 × 5

The prime factor '5' is common in the factorisation of 10, 30 and 45

So, the greatest common factor of 10, 30 and 45 is 5.

5 0
3 years ago
Ariel, who is 15, is 3 years more than<br> twice the age of Hilary. How old is<br> Hilary?
antoniya [11.8K]

Answer:

6

Step-by-step explanation:

15 - 3 = 12, divide that by 2 and your answer is 6.

3 0
3 years ago
Julian walked 6/10 of a mile to his friends house and another 35/100 mile to the store. He walked 1/4 of a mile back home. Julia
AveGali [126]

The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked 1\frac{1}{5} \text{ or } \frac{6}{5} miles.

<u>Solution:</u>  

Given that,

  • Julian walked 6/10 of a mile to his friends house
  • Another 35/100 mile to the store
  • He walked 1/4 of a mile back home

To find total distance walked by Julian we have to add the above stated values. That is, \frac{6}{10} +\frac{35}{100} +\frac{1}{4}

Factors of 10 = 5\times2

Factors of 100 = 5\times2\times5\times2

Factors of 4 = 2\times2

Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,

\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}

\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}

Which can also be written as 1\frac{1}{5}.

So, from the above calculation it can be said that Julian walked 1\frac{1}{5} \text{ miles }.

3 0
3 years ago
In sunlight, a vertical stick has a height of 4 ft and casts a shadow 2 ft long at the same time that a nearby tree casts a shad
marshall27 [118]
Remark
Make up a proportion that relates the tree and its properties to the stick and its properties.

Givens
Stick height (s_h) = 4
Stick shadow(s_s) = 2
Tree shadow = t_s = 18
Tree height = x

Formula
s_h / s_s = x / t_s

Substitute and solve.
4/2 = x / 18  Cross multiply
4*18 = 2 * x
72 = 2x        Divide by 2
72/2 = x       
x = 36

The height of the tree is 36 feet.     
6 0
3 years ago
Write a Let" statement for the unknown, write an equation, and solve the equation. 11. Jane bought a number of records for $7 ea
Advocard [28]

Let n = number of records.

Each record costs $7, so n records cost 7n.

She then spent $3, so the total spent is 3n + 3.

She spent a total of $24, so 3n + 3 must equal 24. That gives us the following equation.

7n + 3 = 24

Subtract 3 from both sides.

7n = 21

Divide both sides by 7.

n = 3

Answer: She bought 3 records.

3 0
4 years ago
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