We are given that the
coordinates of the vertices of the rhombus are:
<span><span>A(-6, 3)
B(-4, 4)
C(-2, 3)
D(-4, 2)
To solve this problem, we must plot this on a graphing paper or graphing
calculator to clearly see the movement of the graph. If we transform this by
doing a counterclockwise rotation, then the result would be:
</span>A(-6, -3)</span>
B(-4, -4)
C(-2, -3)
D(-4, -2)
And the final
transformation is translation by 3 units left and 2 units down. This can still
be clearly solved by actually graphing the plot. The result of this
transformation would be:
<span>A′(6, -8)
B′(7, -6)
C′(6, -4)
D′(5, -6)</span>
It’s add positive 2 every time I believe
if I’m wrong I’m so sorry and please tell me I’m wrong for other that have to use this.
If I’m right ya!! XD
Hope this helps you!
-Pam Pam
REAL BUT NOT RATIONAL :
square root of 2
the golden ratio : 1.618033.....non terminating
square root of 99
Answer:
A) 5x-6y=3
B) 7y=2x+8
B) -2x + 7y = 8 then multiplying "B" by 2.5
B) -5x +17.5y = 20 then adding this to A
A) 5x -6y = 3
11.5y = 23
y = 2
x = 3
Step-by-step explanation:
4
One in 1200 are not particularly good odds. On the other hand, winning the lotto is 1 chance in 13,000,000 which if you've ever played the lotto you know that those odds are good enough to insure that if you played for the rest of your life and you are 18 not expect to live to 80 and you have 104 [given 2 draw a week] chances of winning per year, it likely won't happen. One in 1200 is better but still not good, especially with only 1 draw.
3
As a fraction her probability of winning is 1/2000 which is 0.000833333 as a decimal. You can put that in as
1
÷
1200
=
if you are not sure how your calculator works.
2
Sample Space = {1,2,3,4 .... 1198,1199,1200}
The outcome depends on sophies number. Either 1 number can be chosen or all of them can.
1
The sample space is the integers from 1 to 1200 inclusive.
