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Bingel [31]
3 years ago
14

I need help ASAP

Mathematics
1 answer:
ra1l [238]3 years ago
6 0

Answer:

x =y-3 x=y-3 x=y-3 x=3

2 (y-3) + y= 12 => 3y= 18 => y= 6 => y=6

Step-by-step explanation:

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What is the solution set for the following inequality? 4x – 3 + 6x > 5x + 7
sp2606 [1]

Answer:

you got that

Step-by-step explanation:

wet wet wet

7 0
2 years ago
Read 2 more answers
48 is 30% of what number
natulia [17]
<span>30% * ?= 48 

? = 
48 : 30% = 
48 / (30 : 100) = 
(100 * 48) / 30 = 160</span>
7 0
3 years ago
Can anyone help me please?
andrey2020 [161]

Step-by-step explanation:

5.slope=0

6.equation=y=5

7.slope=undefined(no Slope)

8.equation=x=-1

3 0
3 years ago
As part of quality control, a pharmaceutical company tests a sample of manufacturer pills to see the amount of active drug they
ryzh [129]

Answer:

The z statistic is 0.23.

Step-by-step explanation:

Test statistic (z) = (sample mean - population mean) ÷ sd/√n

sample mean = 104 mg

population mean (mu) = 100 mg

sd = 55 mg

n = 10

z = (104 - 100) ÷ 55/√10 = 4 ÷ 17.393 = 0.23

8 0
4 years ago
An automobile manufacturer has given its jeep a 51.3 miles/gallon (MPG) rating. An independent testing firm has been contracted
Nitella [24]

Answer:

The p-value of the test is 0.2262 > 0.02, which means that the decision is to fail to reject the null hypothesis.

Step-by-step explanation:

An automobile manufacturer has given its jeep a 51.3 miles/gallon (MPG) rating.

At the null hypothesis, we test if the mean is of 51.3, that is:

H_0: \mu = 51.3

An independent testing firm has been contracted to test the actual MPG for this jeep since it is believed that the jeep has an incorrect manufacturer's MPG rating.

This means that at the alternative hypothesis, we test if the mean is different of 51.3, that is:

H_0: \mu \neq 51.3

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

51.3 is tested at the null hypothesis:

This means that \mu = 51.3

After testing 230 jeeps, they found a mean MPG of 51.1. Assume the population variance is known to be 6.25.

This means that n = 230, X = 51.1, \sigma = \sqrt{6.25} = 2.5

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{51.1 - 51.3}{\frac{2.5}{\sqrt{230}}}

z = -1.21

P-value of the test and decision:

The p-value of the test is the probability of the sample mean differing from 51.1 by at least 0.2, which is P(|z| > 1.21), which is 2 multiplied by the p-value of z = -1.21.

Looking at the z-table, z = -1.21 has a p-value of 0.1131.

2*0.1131 = 0.2262

The p-value of the test is 0.2262 > 0.02, which means that the decision is to fail to reject the null hypothesis.

8 0
3 years ago
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