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Vlad1618 [11]
2 years ago
11

3x^2-5=0 completing square

Mathematics
1 answer:
Valentin [98]2 years ago
5 0
It would be good if you add the answers choice, but I guess it’s (b/2)^2
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Match each equation with the number that makes it true.
Burka [1]
Number 1 is 15 number 2 is 9x3=27 and number 3 is 15 and number 4 is 5x7=35 number number 6 is 5 number 7 is 11 and that is about all i know hope this helps
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3 years ago
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Can someone please help me its a short quiz
Marrrta [24]

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Step-by-step explanation:

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4 0
3 years ago
Which equation represents the line that is perpendicular to and passes through (-40,20)?
emmasim [6.3K]

The equation of the perpendicular line to the given line is: y = -5/4x - 30.

<h3>What is the Equation of Perpendicular Lines?</h3>

The slope values of two perpendicular lines are negative reciprocal of each other.

Given that the line is perpendicular to y = 4/5x+23, the slope of y = 4/5x+23 is 4/5. Negative reciprocal of 4/5 is -5/4.

Therefore, the line that is perpendicular to it would have a slope (m) of -5/4.

Plug in m = -5/4 and (x, y) = (-40, 20) into y = mx + b to find b:

20 = -5/4(-40) + b

20 = 50 + b

20 - 50 = b

b = -30

Substitute m = -5/4 and b = -30 into y = mx + b:

y = -5/4x - 30

The equation of the perpendicular line is: y = -5/4x - 30.

Learn more about about equation of perpendicular lines on:

brainly.com/question/7098341

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8 0
1 year ago
The area of a square living room is 256 ft2. Which is the length of the room?
solmaris [256]
Answer=16ft

√256=16ft

length=16ft
6 0
3 years ago
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Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over
Darina [25.2K]

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

We have to find the expression which is equivalent to given  fraction .

\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}

Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

\frac{y-x}{x+y}

This is required expression which is equivalent to given expression.

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3 years ago
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