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DIA [1.3K]
3 years ago
12

Solve the equation 3x2+28x+49=0 by factoring.

Mathematics
1 answer:
Ket [755]3 years ago
6 0

Answer:

=

−

7

3

=

−

7

Step-by-step explanation:

<u> </u>

<u>= </u>

<u>− </u>

<u> </u>

<u>± </u>

<u> </u>

<u>2 </u>

<u>− </u>

<u>4 </u>

<u> </u>

<u> </u>

<u>√ </u>

<u>2 </u>

<u> </u>

<u>x={b}}^{2}-4{a}}{2{a}}} </u>

<u>x=2a−b±b2−4ac​​ </u>

<u>Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula. </u>

<u>3 </u>

<u> </u>

<u>2 </u>

<u>+ </u>

<u>2 </u>

<u>8 </u>

<u> </u>

<u>+ </u>

<u>4 </u>

<u>9 </u>

<u>= </u>

<u>0 </u>

<u>3x^{2}+28x+49=0 </u>

<u>3x2+28x+49=0 </u>

<u> </u>

<u>= </u>

<u>3 </u>

<u>a={3}} </u>

<u>a=3 </u>

<u> </u>

<u>= </u>

<u>2 </u>

<u>8 </u>

<u>b={28}} </u>

<u>b=28 </u>

<u> </u>

<u>= </u>

<u>4 </u>

<u>9 </u>

<u>c={129}{49}} </u>

<u>c=49 </u>

<u> </u>

<u>= </u>

<u>− </u>

<u>2 </u>

<u>8 </u>

<u>± </u>

<u>2 </u>

<u>8 </u>

<u>2 </u>

<u>− </u>

<u>4 </u>

<u>⋅ </u>

<u>3 </u>

<u>⋅ </u>

<u>4 </u>

<u>9 </u>

<u>√ </u>

<u>2 </u>

<u>⋅ </u>

<u>3 </u>

<u>= </u>

<u>− </u>

<u>2 </u>

<u>8 </u>

<u>± </u>

<u>1 </u>

<u>4 over </u>

<u>6 </u>

<u>= </u>

<u>− </u>

<u>2 </u>

<u>8 </u>

<u>+ </u>

<u>1 </u>

<u>4 </u>

<u>6 </u>

<u>x={-28+14}{6} </u>

<u>x=6−28+14​ </u>

<u> </u>

<u>= </u>

<u>− </u>

<u>2 </u>

<u>8 </u>

<u>− </u>

<u>1 </u>

<u>4 </u>

<u>= </u>

<u>− </u>

<u>7 </u>

<u>3 </u>

<u>x=-{7}{3} </u>

<u>x=−37​ </u>

<u> </u>

<u>= </u>

<u>− </u>

<u>7 </u>

<u>= </u>

<u>− </u>

<u>7 </u>

<u>3 </u>

<u> </u>

<u>= </u>

<u>− </u>

<u>7</u>

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