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3 years ago

15

Rohit constructed a rectangular pond of length 40 metre for fish farming is spent rupees 36200 with 4 rounds at rupees 75 find t

he perimeter of the pond

1 answer:

zmey [24]3 years ago

8 0

Answer:

Perimeter = 120m

Step-by-step explanation:

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I need help with this problem

Soloha48 [4]

Answer:

$3.\ \dfrac{3x}{11x}, \dfrac{6}{22}, \dfrac{9}{33},\dfrac{12}{44}$

$4. -18\\5.\ 400$

Step-by-step explanation:

<u>Solution 3:</u>

Equivalent fractions to are to $\frac{3}{11}$ be found out.

<u>Method: </u> By Multiplying both the denominator and numerator with the same number, we can easily find equivalent fractions.

1. Multiply with 2:

$\dfrac{3 \times 2}{11 \times 2}\\\Rightarrow \dfrac{6}{22}$

2. Multiply with 3:

$\dfrac{3 \times 3}{11 \times 3}\\\Rightarrow \dfrac{9}{33}$

3. Multiply with 4:

$\dfrac{3 \times 4}{11 \times 4}\\\Rightarrow \dfrac{12}{44}$

If we try to write in variable form, it can be written as:

$\dfrac{3x}{11x}$

where x is any number.

---------------

<u>Solution 4:</u>

$(2x-10)$ when $x=-4$

$2 \times (-4) -10\\\Rightarrow -8 -10\\\Rightarrow -18$

------------

<u>Solution 5:</u>

$(10a)^2, a=-2\\\Rightarrow \{10 \times (-2)\}^2\\\Rightarrow (-20)^2\\\Rightarrow 400$

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3 years ago

If the outliers are not included, what is the mean of the data set?

luda_lava [24]

The mean of the numbers is c. 67

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3 years ago

The ampitude/frequency/period of y=1/4cos1/2x is 4 pie

Fantom [35]

Amplitude: 1/4 (= |a|)
Frequency: 1/2 (= |b|)
Period: 4pi (= 2pi/|b|)

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3 years ago

Help eeeeeeeeeeeeeeeeeeeee

leva [86]

3.9
Hope that helps
You can use the app math.way also

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‼️‼️10 points‼️‼️

My name is Ann [436]

Answer:

The correct answer is B.

Step-by-step explanation:

There is no clear rule regarding the relationship with these numbers. So it is not linear.

Good Luck!

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3 years ago

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