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2 years ago

Can anyone help???!!!! 7 points

Mathematics

1 answer:

Mashcka [7]2 years ago

8 0

Answer:

Section S

Step-by-step explanation:

Its because it is in all of the squares. Also please mark as brainliest i need the 5 corwns cause i keep getting points but I'm not leveling up without the crowns, thanks : )

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What is the simplified expression for 3^3 x 3^3/ 3^4

Juli2301 [7.4K]

Answer:

Step-by-step explanation:

$\frac{3^{6} }{3^{4} }$

$3^{2}$

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3 years ago

Plz help me!!with this!!

ikadub [295]

the surface area of that rectangular prism is 247.5.

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3 years ago

In a game of checkers there are 12 red pieces and 12 black game pieces.Julio is setting up the board to begin playing. what is t

Bond [772]

Since there are equal numbers of pieces, the chances of Julio getting a red on the first pull is 12/24 or 1/2 (reduced)

However on the second pull there are only 11 reds (Julio pulled one out) out of 23 remaining pieces so the chances of pulling the second red are 11/23

Now multiply those possibilities:
1/2 x 11/23 and you will get 11/46 which is the probability of pulling two reds in a row. 11/46 is the answer.

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3 years ago

Write 350 as a product of primes

LiRa [457]

Answer:

$350 = 2 \times 5 \times 5 \times 7$

Step-by-step explanation:

$350 = 2 \times 5 \times 5 \times 7$

4 0

2 years ago

Read 2 more answers

Six stand-up comics, A, B, C, D, E, and F, are to perform on a single evening at a comedy club. The order of performance is

kiruha [24]

Answer:

a) 1/6

b) 1/36

c) 1/720

d) 1/3

Step-by-step explanation:

a) Any of the six comics can perform in the fourth place, so there is one chance in six that Comic F is the one that performs fourth.

$P(F=4th)=1/6$

b) In this case, we have two conditions. Both are independent of each other, so the probability of both happening is the product of the probabilities of each happening individually:

$P(D=4th \&B=2nd)=P(D=4th)\cdot P(B=2nd)=(1/6)\cdot(1/6)=1/36$

c) This combination is one in all possible orders of perform. The amount of combinations of orders is n!=6!=720 possible combinations. So the probability of this specific order is:

$P(F, D, B, A, C, E)=1/720$

d) In this case, of the six possible comics performing in the last place, we calculate the probability of 2 of them being in that place. So the probability is:

$P(C=6th\,or\, E=6th)=2/6=1/3$

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3 years ago