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Novay_Z [31]
3 years ago
8

In a game of checkers there are 12 red pieces and 12 black game pieces.Julio is setting up the board to begin playing. what is t

he probability that the first two checkers he pulls from the box at random will be two red checkers . Can you please show me how to work this out ?
Mathematics
1 answer:
Bond [772]3 years ago
4 0
Since there are equal numbers of pieces, the chances of Julio getting a red on the first pull is 12/24  or 1/2 (reduced)

However on the second pull there are only 11 reds (Julio pulled one out) out of 23 remaining pieces so the chances of pulling the second red are 11/23

Now multiply those possibilities: 
 1/2  x 11/23 and you will get 11/46 which is the probability of pulling two reds in a row.  11/46 is the answer.  
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Which interval would not be used for the stems of a stem-and-leaf plot? 10 100 1 5
IrinaK [193]
100 because that just isn’t possible
5 0
3 years ago
Solve the equation −2w+4=−12. URGENT Solution
VMariaS [17]

Answer:

The solution is w=8

Step-by-step explanation:

we have

-2w+4=-12

Solve for w

That means -----> isolate the variable w

Subtract 4 both sides

-2w+4-4=-12-4

-2w=-16

Divide by -2 both sides

-2w/-2=-16/-2

w=8

7 0
3 years ago
A football coach is trying to decide: When a team is ahead late in the game, which strategy is better?
PSYCHO15rus [73]

Answer:

You are more likely to win by playing regular defense.

Step-by-step explanation:

Assume out of 100 reviewed games, there were 50 regular defense games and 50 prevent defense games. And out of 50 regular defense games, 38 were win, 12 were lose. And out of 50 prevent defense game, 29 were win, 21 were lose.

Probability to win the game by playing regular defense is:

P(win | regular) = 38/50 = 0.76

Probability to win the game by playing prevent defense is:

P(win | prevent) = 29/50 = 0.58

Since the probability of winning by regular defense game is more than prevent defense game (0.76 > 0.58), you are more likely to win by playing regular defense.

5 0
3 years ago
Read 2 more answers
Which operation could we perform in order to find the number of milliseconds in a year? 60 * 60 * 24 * 7 * 365 1000 * 60 * 60 *
Tom [10]
Use the following abbreviations:
y = year,
d = day,
h = hour,
min = minute,
s = second,
ms = millisecond.

Then
1 \, y = (1 \, y)*(365 \,  \frac{d}{y} )*(24 \,  \frac{h}{d} )*(60 \,  \frac{min}{h} )*(60 \,  \frac{s}{min} )*(1000 \,  \frac{ms}{s} )

Therefore, the correct calculation is
1000 * 60 * 60 * 24 * 365

Answer: 1000 * 60 * 60 * 24 * 365

4 0
3 years ago
If f(x)=2−x12 and g(x)=x2−9, what is the domain of g(x)÷f(x)?
Keith_Richards [23]
\bf \begin{cases}
f(x)=2-x^{12}\\
g(x)=x^2-9\\
g(x)\div f(x)=\frac{g(x)}{f(x)}
\end{cases}\implies \cfrac{x^2-9}{2-x^{12}}

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to undefined.

now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.

\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\
-------------------------------\\\\
\cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}

so, the domain is all real numbers EXCEPT that one.
4 0
3 years ago
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