Y = 76 x = 16 Sorry if I am wrong
Hope it helped
Exponential would be the correct answer I believe...
Answer and Explanation: The answer is in the 1st image, and the explanation is in the 2nd image.
<h3>
<u>Question:</u></h3>
Find the equation of line perpendicular to x = 1 and passing through (7, 11)
<h3><u>Answer:</u></h3>
The equation of line Perpendicular to x = 1 and passing through (7, 11) is y = 11
<h3><u>
Solution:</u></h3>
Given that line is perpendicular to x = 1 and passing through (7, 11)
We have to find the equation of line
The equation of the line in standard form is x = 1
This is a vertical line, so the perpendicular line will be a horizontal line of the form y = b
Since we are given that the line should pass through the point (7, 11) then the equation of the line is y = 11
Answer:
Step-by-step explanation:
prime factorization
40y³ = 2³×5y³
625 = 5⁴
Greatest common factor = 5
40y³ - 625 = 5(8y³ - 125)
Note that 8y³ - 125 is the difference of cubes.
8y³ - 125 = (2y)³ - 5³ = (2y-5)((2y)² + 2y·5 + 5²) = (2y-5)(4y² + 10y + 25)
40y³ - 625 = 5(2y-5)(4y² + 10y + 25)
