1, 6, 22, 69, 210

HELP ASAP PLS AND THANKS!!!!

likoan [24]

The first one is the correct answer

7 0

3 years ago

Read 2 more answers

QUICK Find the area of the shaded region. Use 3.14 for pi.

ivolga24 [154]

Answer:

The shaded region is $353.25m^2$ .

Step-by-step explanation:

The area of a circle is defined by the multiplication of the square of its radius, or half its diameter, by pi, or simply $A=\pi r^2$ .

15m is the radius of the large circle, and also the diameter of the smaller circles.

The area of the shaded region will be the subtraction of the area of the two smaller circles from the area of the larger circle.

As such:

$A=\pi(15)^{2}-2(\pi(\frac{15}{2} )^{2})\\\\A=(3.14)(15)^{2}-2(3.14)(\frac{15}{2} )^{2}\\A=706.5-353.25\\A=353.25$

4 0

2 years ago

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Which fraction correctly shows the probability of14 favorable outcomes and 37 possible outcomes?

zepelin [54]

Answer: 14/37

Step-by-step explanation:

7 0

2 years ago

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5 hours 15 min + 3 hours 33 min show the working as well

Alika [10]

Answer:

8 hours 48 mins

Step-by-step explanation:

h m

5:15

+3:33

--------------

8:48

or

5 hours + 3 hours =8 hours,

15 mins + 33 mins = 48 mins

Therefore, it's 8 hours 48 mins.

7 0

2 years ago

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Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

3 years ago