Question

Calculate the change in temperature (ΔT) that occurs when 8000 J of energy (q) is used to heat up a mass (m) of 75 g of water. (you already know the value of the specific heat of water, C) (round your answer to the nearest whole number)

Answer 1

Answer:

The change in temperature that occurs when 8000 J of heat is used by a mass 75 g of water is 25.4 °C

Explanation:

H = mc ΔT

m = 75 g

c = 4. 200 J/ g °C

H = 8000 J

ΔT =?

Rearranging the formula, making ΔT the subject of formula;

ΔT = H / m c

ΔT = 8000 / 75 * 4.200

ΔT = 8000 / 315

ΔT = 25.4 °C

Answer 2

Answer:

The change in temperature ΔT that occurs when 8000 J of energy (q) is used to heat up a mass (m) of 75 g of water is 25°C

Explanation:

The formula for change in heat supplied to a body is given as follows;

ΔH = m·C·ΔT

Where:

ΔH = Heat supplied to the body = 8000J

m = Mass of the body = 75 g

ΔT = $T_{(Final)} - T_{(Initial)}$ = Temperature change experienced by the body

c = Specific heat capacity of water = 4.186 J/g

Therefore, 8000 J = 75 g × 4.186 J/(g·°C) × ΔT

Therefore;

$\Delta T = \frac{8000 \, J }{75 \, g \times 4.186 \, J/(g\cdot ^{\circ}C) } = 25.48 ^{\circ}C$

Hence the change in temperature ΔT that occurs when 8000 J of energy (q) is used to heat up a mass (m) of 75 g of water rounded to the nearest whole number = 25°C.