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4 years ago

In which of the following phases of matter do molecules have the lowest amount of energy?

Chemistry

2 answers:

Elden [556K]4 years ago

5 0

Answer:

C. Solid

Explanation:

It's most about the kinetic energy, when molecules have the least amount of room to move around, they have the least amount of energy.

For example if you think about gas and how spread out the molecules are in order to evaporate, there it the highest amount of energy there.

Savatey [412]4 years ago

4 0

Answer: solid

Explanation: This is because they only vibrate in place. Particles in the liquid state move faster than particles in the solid state. Therefore, they have more kinetic energy.

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The combustion of carbohydrates and the combustion of fats are both exothermic processes, yet the combustion of carbohydrates is

Julli [10]

Explanation:

There are two aspects of a reaction:

Thermodynamics:

Combustion of the compound is reaction with oxygen.

The carbohydrates contain more content of oxygen as compared to fats.

Hence, carbohydrates have lot of oxygen content which are already partially oxidized as compared to fats. Hence, combustion of the carbohydrates is a faster process.

Kinetics:

The molecular reacts also shows that the combustion of the carbohydrates is a faster process.

7 0

4 years ago

If 45.0 mL of ethanol (density=0.789 g/mL) initially at 9.0 C is mixed with 45.0 mL of water (density=1.0 g/mL) initially at 28.

Klio2033 [76]

Answer : The final temperature of the mixture is $22.7^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

And as we know that,

Mass = Density × Volume

Thus, the formula becomes,

$(\rho_1\times V_1)\times c_1\times (T_f-T_1)=-(\rho_2\times V_2)\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of ethanol = $2.3J/g^oC$

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of ethanol

$m_2$ = mass of water

$\rho_1$ = density of ethanol = 0.789 g/mL

$\rho_2$ = density of water = 1.0 g/mL

$V_1$ = volume of ethanol = 45.0 mL

$V_2$ = volume of water = 45.0 mL

$T_f$ = final temperature of mixture = ?

$T_1$ = initial temperature of ethanol = $9.0^oC$

$T_2$ = initial temperature of water = $28.6^oC$

Now put all the given values in the above formula, we get

$(0.789g/mL\times 45.0mL)\times (2.3J/g^oC)\times (T_f-9.0)^oC=-(1.0g/mL\times 45.0mL)\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.7^oC$

Therefore, the final temperature of the mixture is $22.7^oC$

4 0

3 years ago

Dimitri Mendeleev organized an early version of the Periodic Table in order of increasing __________.

omeli [17]

c) Atomic Mass.

Hope it is helpfull

6 0

3 years ago

Which product of petroleum is normally used as fuel in cars and light vehicles

Elena L [17]

Answer:

mostly gasoline in cars nowadays

8 0

4 years ago

Read 2 more answers

Milk of magnesia has the chemical formula Mg(OH)2. What is the mass of 3.2 moles of milk of magnesia? The molar Mass of magnesiu

GenaCL600 [577]

To calculate the mass of milk of magnesia given, we need certain data like molar mass of the compound which needs the atomic mass of the atoms in the compound. We calculate as follows:

Molar mass of <span>Mg(OH)2 = 24.3 g/mol + (2 x (16 + 1.0)) = 58.30 g/mol

Mass = 3.2 mol (</span>58.30 g/mol) = 186.56 grams

3 0

3 years ago