☃️ Chemical formulae ➝ 
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<u>How to find?</u></h3>
For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.
<h3>
<u>Solution:</u></h3>
Atomic weight of elements:
Ca = 40
C = 12
O = 16
❍ Molecular weight of
= 40 + 12 + 3 × 16
= 52 + 48
= 100 g/mol
❍ Given weight: 10 g
Then, no. of moles,
⇛ No. of moles = 10 g / 100 g mol‐¹
⇛ No. of moles = 0.1 moles
☄ No. of moles of Calcium carbonate in that substance = <u>0.1 moles</u>
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Answer:
B
Explanation:
Molarity = 0.010M
Volume = 2.5L
Applying mole-concept,
0.010mole = 1L
X mole = 2.5L
X = (0.010 × 2.5) / 1
X = 0.025moles
0.025moles is present in 2.5L of NaOH solution.
Molar mass of NaOH = (23 + 16 + 1) = 40g/mol
Number of moles = mass / molar mass
Mass = number of moles × molar mass
Mass = 0.025 × 40
Mass = 1g
1g is present in 2.5L of NaOH solution
Answer:
your answer will be between 16-17 moles
Explanation:
The combustion of butane is 2 C4H10 + 13 O2 = 8 CO2 + 10 H2O. Every two moles of C4H10 can produce 10 moles of water,
Answer:
2.288 Moles of NH₄NO₃
Explanation:
The Balance chemical equation is as follow:
(NH₄)₂CO₃ + 2 HNO₃ → 2 NH₄NO₃ + H₂O + CO₂
To solve this problem we will do following steps:
Finding moles of Ammonium Carbonate:
As we know,
Moles = Mass / M.Mass
So,
Moles = 110 g / 96.08 g/mol
Moles = 1.144 moles
Calculating moles of Ammonium Nitrate:
According to balance chemical equation;
1 mole of (NH₄)₂CO₃ produces = 2 moles of NH₄NO₃
So,
1.144 moles of (NH₄)₂CO₃ will produce = X moles of NH₄NO₃
Solving for X,
X = 2 moles × 1.144 moles ÷ 1 mole
X = 2.288 moles of NH₄NO₃
Answer:
Percent yield = 21%
Explanation:
Find:
Percent yield
Computation:
1 mol O₂ produces 2 mol NO₂
So,
10 mol O₂ produces 20 mol NO₂
Percent yield = [Actual yield / Theoretical yield]100
Percent yield = [4.2 / 20]100
Percent yield = 21%
