The required solution is ∠RQT = 202° and ∠QTS = 51°
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<h3>What is a cyclic quadrilateral?</h3>
A cyclic quadrilateral is a quadrilateral which has all its four vertices lying on a circle. It is also called as inscribed quadrilateral.
Its main property is that the sum of opposite angles of inscribed quadrilateral is always 180 degrees.
Now, the given circle has a cyclic quadrilateral QRST in which it is given that ∠RQT = 202° and ∠QRS = 129°
Since,sum of the opposite angles of a cyclic quadrilateral = 180°
⇒∠QTS + ∠QRS = 180°
⇒ ∠QTS + ∠129° = 180°
⇒ ∠QTS = 180° - ∠129°
⇒ ∠QTS = 51°
Hence,the requires angles are ∠RQT = 202° and ∠QTS = 51°.
More about cyclic quadrilateral :
brainly.com/question/14323008
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Answer:
9x(4+8y+3y)
Step-by-step explanation:
36x+72xy+27xy
9x(4+8y+3y)
Answer:
243
Step-by-step explanation:
6x3x13.5=243
Since these are parabolas with y being squared, the standard form of such a parabola with vertex at (h, k) is
<span>x = a(y - k)^2 + h </span>
<span>There are no steps. Just look at what is inside the parentheses and compare it to (y - k) with k = -3. </span>
<span>Then look at what is added and compare it to h = -1. </span>
<span>For instance, A has (y + 1) in parentheses. So k = -1. And it has -3 added, so h = -3. That would be a vertex at (-3, -1).</span>
