Answer:
1. Wildlife
2. Seafood
Explanation:
1. Wildlife refers to the species which are not domesticated by the humans and they live as a wild organisms in the areas which are not interfered with the humans. In the given question, the wild creatures that live on the land therefore are considered a part of the wildlife.
2. Seafood refers to the species which are considered as food which humans get from the sea. In the given question, the Blue Fin fishes are considered a seafood therefore.
Answer:
2 HBr (aq) + CaCO3 (s) → CaBr2 (aq) + CO2 (g) + H2O (l)
Answer:
The equilibrium concentration of CH₃OH is 0.28 M
Explanation:
For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)
The equilibrium constant (Keq) is given for the following expresion:
Keq= 
=14.5
Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.
We have:
(CH3OH)= ?
(CO)= 0.15 M
(H2)= 0.36 M
So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:
14.5= 
14.5 x (0.15 M) x 
= (CH₃OH)
0.2818 M = (CH₃OH)
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