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Sergeu [11.5K]
3 years ago
10

Is jewelry gold an element, compound or mixture?

Chemistry
1 answer:
suter [353]3 years ago
3 0
Gold is a mixture Becasue it contains more than one element
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in a Grignard reagent, the carbon bonded to the magnesium has a partial ________ charge, because carbon is ________ electronegat
nekit [7.7K]

Answer:

well idk but i will take the points

Explanation:

7 0
3 years ago
Write an equation that shows the formation of a chromium(ii) ion from a neutral chromium atom.
daser333 [38]
The   equation  that  shows  the  formation  of  chromium (ii) ion  from  neutral  chromium  atom  is  as  follow
Cr ---> cr^2+   +  2e-
Cr^2+ is  the  chromium  ion   with  oxidation  state  of  two  which  is  one  of  the  common  ion  of  chromium.  Other  common  ion   of  chromium  include  chromium  of  oxidation  state  6  and  3

8 0
4 years ago
Read 2 more answers
Liz puts a 1 kg weight and a 10 kg on identical sleds. She then applies a 10N force to each sled. Which does not explain why the
Soloha48 [4]

(05.01)

Which statement best explains if the graph correctly represents the proportional relationship y = 0.5x? (4 points)

<span>Yes, the points shown on the line would be part of y = 0.5xYes, all proportions can be shown on a graph of this lineNo, the points shown would not be part of y = 0.5xNo, proportions cannot be represented on a graph</span>
7 0
4 years ago
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50.0 mL of an HNo3 solution were titrated with 36.90 mL of a 0.100 M LiOH solution to reach the equivalence point. What is the m
sleet_krkn [62]
Answer: 0.0738 M

Explanation:


1) Chemical equation:

<span>HNO₃ + LiOH → LiNO₃ + H₂O
</span>

2) Mole ratios:

1 mol HNO₃ neutralizes 1 mol LiOH

3) Number of moles of H⁺ from HNO₃:

M = n / V ⇒ n = M × V = 0.050 liter × M

4) Number of moles of OH⁻ from LiOH

M = n / V ⇒ n = M × V = 0.03690 liter × 0,100 M

5) Equivalence point:

number of moles of H⁺ = number of moles of OH⁻

⇒ 0.0500 × M = 0.03690 × 0.100 

⇒ M = 0.03690 × 0.100 / 0.0500 = 0.0738 M
<span />
3 0
4 years ago
What is the equilibrium expression for the reaction below?
Mariana [72]

Answer:

A. K=\frac{[N_2O]^2}{[N_2]^2[O_2]}

Explanation:

Hello there!

In this case, for us to figure out the appropriate equilibrium expression, it will be firstly necessary for us to recall the law of conservation of mass which states that the equilibrium constant of an equilibrium chemical reaction is written by dividing the products and reactants and including the stoichiometric coefficients as exponents. In such a way, for the given reaction, we will have:

K=\frac{[N_2O]^2}{[N_2]^2[O_2]}

As N2O is the product whereas N2 and O2 are reactants; thus, the equilibrium expression will be A.

Regards!

6 0
3 years ago
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