Answer:

Explanation:
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In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:

Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.
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4.The other light bulb will stay on and glow brightly.
Answer:
CH3 - CH2 - NH - C(CH3)3
Explanation:
The 1HNMR is the acronym for Proton nuclear magnetic resonance and it is used in chemistry or Chemical laboratory for the analysis and identification of compounds.
In order to be able to answer the question accurately you have to have the tables containing all the values for chemical shift. The Chemical shift is measured in ppm and it occur due to Resonance frequency variation.
From the table, a singlet at 1.15 ppm (9H) is - C(CH3)3.
A singlet at d 0.9 ppm (1H) shows the presence of a secondary amine group, that is -R2NH group.
A triplet at 1.10 ppm (3H) shows that we have;
CH3- CH2-
A quartet at 2.6 ppm (2H) shows that we have;
-CH2 - CH3.
Therefore, joining all together we have;
CH3 - CH2 - NH - C(CH3)3.
Kindly check attached file for the picture of the structure.
<u>Answer:</u> The new water level of the cylinder is 24.16 mL
<u>Explanation:</u>
To calculate the volume of water displaced by silver, we use the equation:

Density of silver = 10.49 g/mL
Mass of silver = 35.2 g
Putting values in above equation, we get:

We are given:
Volume of graduated cylinder = 20.8 mL
New water level of the cylinder = Volume of graduated cylinder + Volume of water displaced by silver
New water level of the cylinder = (20.8 + 3.36) mL = 24.16 mL
Hence, the new water level of the cylinder is 24.16 mL
Answer:
286 kPa
Explanation:
Boyles law states that volume of gas is inversely proportional to pressure o gas for a fixed amount of gas at constant temperature
P1V1 = P2V2
where P1 is pressure and V1 is volume at first instance
P2 is pressure and V2 is volume at the second instance
substituting the values in the equation
229 kPa x 4.0 L = P2 x 3.2 L
P2 = 286.25 kPa
the new pressure is 286 kPa