Answer:
wat
Step-by-step explanation:
Answer:
b)0.83^6
probability of Kobe Bryant making all of his next 6 free throw attempts
=probability of Kobe Bryant making first free throw attempts x
probability of Kobe Bryant making second free throw attempts x
probability of Kobe Bryant making third free throw attempts x
probability of Kobe Bryant making fourth free throw attempts x
probability of Kobe Bryant making fifth free throw attempts x
probability of Kobe Bryant making sixth free throw attempts
= P(make 1) x P(make 2nd) x P(make 3rd) x P(make 4th) x P(make 5th)x P(make 6th) = 0.83^6
Answer:
Using BODMAS
first solve division, then go for addition or subtraction
Answer:
3
Step-by-step explanation:
Answer:
Step-by-step explanation:
