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Igoryamba
2 years ago
15

Evaluate f(-3) for f(x) = 2^x a. 1/8 b. -8 c. 8 d. -6

Mathematics
1 answer:
pickupchik [31]2 years ago
6 0

Answer:

A

Step-by-step explanation:

f(-3) = 2^-3

to get rid of a negative in an exponent, move the whole thing to the denominator.

1/(2^3)

2^3 = 2×2×2

1/(2×2×2)

1/8

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The radius of the circle whose equation is (x-3)^2 + (y+1)^2 = 16 is
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(x-a)^{2}+(y-b)^{2}=r^{2}

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quadrilateral paid is a rectangle whose diagonals have the endpoints p(-3, -2)i(4, -7) and a(4, -2)d(-3, -7). find the diagonals
julia-pushkina [17]

Answer:

The intersection point of diagonals is (0.5,-4.5).

Step-by-step explanation:

The end points of first diagonal are p(-3, -2) and i(4, -7).

The end points of second diagonal are a(4, -2) and d(-3, -7).

If a line passing through two points, then the equation of line is

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

The equation of first diagonal is

y-(-2)=\frac{-7-(-2)}{4-(-3)}(x-(-3))

y+2=\frac{-5}{7}(x+3)

7y+14=-5(x+3)

7y+14=-5x-15

5x+7y=-29                         .... (1)

The equation of second diagonal is

y-(-2)=\frac{-7-(-2)}{-3-4}(x-4)

y+2=\frac{-5}{-7}(x-4)

7y+14=5(x-4)

7y+14=5x-20

5x-7y=34                         .... (2)

Add equation (1) and (2),

10x=5

x=0.5

Put this value in (1).

5(0.5)+7y=-29

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The intersection point of diagonals is (0.5,-4.5).

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3 years ago
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