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belka [17]
3 years ago
10

Plz help me if you're nice. If wrong answer i'll report you

Mathematics
1 answer:
Anna [14]3 years ago
5 0

Answer

z= 14

Step-by-step explanation:

4( 2z-3) -5(z-6) =3 *20

8z-12-5z+30=60

3z+18=60

3z=60-18

3z=42

z= 14

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Find h(g(n)) when h(n) = 2n + 5<br> and g(n) = n +4
Evgen [1.6K]

Answer:

2n+13

Step-by-step explanation:

h(g(n))\\h(n)=2n+5\\g(n)=n+4\\h(n+4)=2(n+4)+5\\=2n+8+5\\=2n+13

5 0
2 years ago
Orly uses 3 cups of raisins for every 10 cups of trail mix she makes. How many cups of trail mix will she make if she uses 12 cu
MrRa [10]
This is a proportion problem
3/10= 12/x
Now cross multiply and divide
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4 0
3 years ago
The town librarian bought a combination of new-release movies on DVD for $20 and classic movies on DVD for $8. Let x represent t
Galina-37 [17]

Answer:

x = 1, y = 60

Step-by-step explanation:

Value of new-releases (x) = $20 each

Value of classic (y) = $8 each

Total budget = $500

Equation : 20x + 8y = 500

The librarian wants to purchase maximum DVDs. She can get more DVDs of classic movies for $8 as they are less costly.

Lets assume the librarian buys at least one new-release DVD.

x=1

20x + 8y = 500

8y + 20(1) = 500

y = 60

<em>Therefore, in a budget of $500, the librarian can purchase 60 classic movies and 1 new-release.</em>

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8 0
3 years ago
Use the distributive property to generate an equivalent expression for<br> 2(10x-3)
mr Goodwill [35]

Answer:

20x - 6

Step-by-step explanation:

You just multiply 2 by 10x and by -3

5 0
2 years ago
Read 2 more answers
Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel
GarryVolchara [31]

Answer:

The unusual X values ​​for this model are: X = 0, 1, 2, 7, 8

Step-by-step explanation:

A binomial random variable X represents the number of successes obtained in a repetition of n Bernoulli-type trials with probability of success p. In this particular case, n = 8, and p = 0.53, therefore, the model is {8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}. So, you have:

P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024

P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215

P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848

P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912

P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695

P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431

P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371

P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442

P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062

The unusual X values ​​for this model are: X = 0, 1, 7, 8

6 0
3 years ago
Read 2 more answers
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