Plz help me if you're nice. If wrong answer i'll report you

Find the slope of the line that passes through (10,7) and (1,9)

Simora [160]

Answer:

Step-by-step explanation:

Use the slope formula

(x2-x1)/(y2/y1)

substitute the values

(1-10)/(9-7)

solve

-9/-2

simplify

9/2 or 4.5

6 0

3 years ago

What is the following sum? 4(5√x^2 y) +3(5√x^2 y)

Levart [38]

the answer is 35 x √ 2 y

3 0

3 years ago

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A random sample of 20 students yielded a mean of ¯x = 72 and a variance of s2 = 16 for scores on a college placement test in mat

Helen [10]

Answer:

The 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

Step-by-step explanation:

1) Data given and notation

$s^2 =16$ represent the sample variance

s=4 represent the sample standard deviation

$\bar x$ represent the sample mean

n=20 the sample size

Confidence=98% or 0.98

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$

On this case the sample variance is given and for the sample deviation is just the square root of the sample variance.

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

$df=n-1=20-1=19$

Since the Confidence is 0.98 or 98%, the value of $\alpha=0.02$ and $\alpha/2 =0.01$ , and we can use excel, a calculator or a table to find the critical values.

The excel commands would be: "=CHISQ.INV(0.01,19)" "=CHISQ.INV(0.99,19)". so for this case the critical values are:

$\chi^2_{\alpha/2}=36.191$

$\chi^2_{1- \alpha/2}=7.633$

And replacing into the formula for the interval we got:

$\frac{(19)(16)}{36.191} \leq \sigma^2 \leq \frac{(19)(16)}{7.633}$

$8.400 \leq \sigma^2 \leq 39.827$

So the 98% confidence interval for the variance in the pounds of impurities would be $8.400 \leq \sigma^2 \leq 39.827$ .

7 0

3 years ago

A group of friends were working on a student film. They spent all their budget on props and costumes. They spent $243 on props,

SVETLANKA909090 [29]

Answer:

The total budget for their student film was $540

Step-by-step explanation:

The total percentage of any quantity is 100%

∵ A group of friends was working on a student film

∵ They spent all their budget on props and costumes

∴ The total budget of the props and costumes = 100%

∵ They spent $243 on props

∵ They spent 55% of the total budget on costumes

→ Find the percentage of the props

∴ The percentage of the props = 100% - 55%

∴ The percentage of the props of the total budget = 45%

→ That means 45% of the total budget = 243

∵ 45% × total budget = 243

→ Change the percent to a number by divide it by 100

∵ 45% = 45 ÷ 100 = 0.45

∴ 0.45 × total budget = 243

→ Divide both sides by 0.45

∴ The total budget = 540

∴ The total budget for their student film was $540

4 0

3 years ago

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En un pozo petrolìfero produce cada dia 2680 barriles de petroleo. Si cada barril contiene 159 litros de petroleo, cuantos litro

Aliun [14]

Answer:

426,120 litros se producen en un día Se producen

12,783,600 litros por mes (para un cálculo de 30 días en un mes)

Step-by-step explanation:

Aquí, debemos calcular la cantidad en litros de petróleo producido en un pozo petrolero.

Se nos dice que se producen 2.680 barriles por día y cada barril contiene 159 litros de petróleo.

La producción diaria en litros es, por lo tanto, de 159 * 2680 = 426,120 litros.

Ahora, para la producción mensual, supongamos que hay 30 días en un mes, la cantidad en litros producidos por mes sería la cantidad diaria multiplicada por la cantidad de días en un mes.

Matemáticamente, eso sería 30 * 426,120 = 12,783,600 litros

4 0

4 years ago