(3-6z)(3+6z) what is the product if this equation

Mathematics

1 answer:

Alina [70]2 years ago

5 0

9514 1404 393

Answer:

9 -36z²

Step-by-step explanation:

The form of the given product matches the form of the "special product" ...

(a -b)(a +b) = a² -b² . . . . . . . factoring of the difference of squares

You have a=3, b=6z, so the product is ...

(3)² -(6z)² = 9 -36z²

Additional comment

If you like, you can work this out using the distributive property.

(3 -6z)(3 +6z) = 3(3 +6z) -6z(3 +6z) . . . . use the distributive property

= 9 +18z -18z -36z² . . . . . . . use the distributive property again

= 9 -36z² . . . . . . . . . collect terms

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