Answer:
4.5 seconds pass before reaching the ground
Step-by-step explanation:
The height of the object is given by the following equation:
How many seconds pass before reaching the ground
It hits the ground when h(t) = 0. So
There are no negative instants of time, so only the positive answer interests to us.
4.5 seconds pass before reaching the ground
Answer:
Explanation:
1. Quantiy R
Decay model:
That is a first order reaction, whose solution is:
The value at t = 0, R(0) = 100 is R₀.
Thus, the law is:
2. Quantity S
Decay model:
That is a zero order kinetic, whose solution is:
The value at t = 0, S(0) = 125 is S₀
Thus, the law is:
<u>3. At what time will there ve equal quantities of both substances?</u>
You must solve the system doing R(t) = S(t)
That equation must be solved by graphing or by consecutive iterations
Note that when t = 0 R(t) = 100 and S(t) = 125. From, that the quantities decreases.
Subsitute with t = 10.
Then, the time is greater than 10.
Substitute with t = 15
t = 20
t = 25
t = 24
Hence, 24 seconds is a satisfactory solution.
The graph attached shows that the intersection point is at t ≈ 23.548 seconds, confirming that 24 seconds is the best solution rounded to an integer number.
